Answer:
The original area would be multiplied by the scale factor of 2² to get the new area.
Step-by-step explanation:
If you double the radius lets so lets do an example
(a=πr²) so
if x is the radius the area would be x²π
double the radius so 2x then the area would be
(2x)²π so 4x²π
4x²π/x²π= 4 so its 4 times greater or
D the last answer or The original area would be multiplied by the scale factor of 2² to get the new area.
Bibby
m=y2−y1x2−x1=15−75−1=84=2y−y1=m(x−x1)⟺(x1,y1)=(1,7)y−7=2(x−1)y−7=2x−2y=2x−2+7 y=2x+5
A) x + y = 17
B) x - y = 27
Adding both equations:2x = 44
x = 22
y = -5
Answer:
diameter = m - c
Step-by-step explanation:
In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).
The sum of the lengths of the tangents from points A and B on side "c" is ...
(b-r) +(a-r) = c
(a+b) -2r = c
Now, the problem statement defines the sum of side lengths as ...
a+b = m
and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...
m -d = c
m - c = d . . . . add d-c
The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.
Answer:
8
Step-by-step explanation:
3+5=8