Comparing map distance to real distance we get 2cm/4km. That means 1cm = 2km.
So the map distance is half the real distance (well, technically not as one is in cm and the other in km but it’s enough to think this way) and a real distance of 10km must mean a map distance of half that (again ignoring the units) so we get 5cm.
Answer: 7
Step-by-step explanation: there are 4 full circles so that equals 4. 1+1=2, 1/8+7/8=1. 4+2+1=7
To find the Chebyshev's inequality, P | Xn - E(X)| <= δ/4 >= 1 - (δ^2/25)/(δ^2/16) = 1 - (16/25) = 9/25 = 0.36
The answer in this question which is the probability that the average of the physicist's measurement is within δ/4 units of the actual specific gravity is at least 0.36%
Answer:
Part 4) 
Part 5) 
Part 6) 
Step-by-step explanation:
Part 4) Find ER
we know that
In the right triangle ERF
Applying the Pythagorean Theorem
substitute the given values
solve for ER
Part 5) Find DF
we know that
In the right triangle DRF
Applying the Pythagorean Theorem
substitute the given values
simplify
Part 6) Find DE
we know that
----> by segment addition postulate
we have
substitute
Answer: You need to show the question for me to answer it. In other words, provide more context
Step-by-step explanation:
