If f(x)=x²+2 and g(x)=x²+5 then the domain of the (fog) (x) is (-∞,∞).
Given the f(x)=x²+2 and g(x)=x²+5
We have to find the domain of the (fog) (x)
The domain of a function is the set of all possible inputs for the function. For example, the domain of f(x)=x² is all real numbers, and the domain of g(x)=1/x is all real numbers except for x=0.
then,(fog) (x)= (x²+5)²+ 2
=x⁴+25+10x²+2
= x⁴+27+10x²
Now on any real value of x the value of (fog) (x) exists therefore (fog) (x) can take all the values of the real number.
So domain (fog) (x)= (-∞,∞).
Learn more about the domain here: brainly.com/question/26098895
#SPJ10
Answer:
Its very easy all you have to do is substitute the -3 into the x
Step-by-step explanation:
Answer:
For the first one, put the input(0) in the place of x. This would make it look like this, 3x0+5
The x is a times sign, which was added when you add the number.
The rest goes like this,
3x0=0
0+5=5
Ouput= 5
Answer:
The center of dilation of ABCD to EFGH is (0, 0), and the scale factor is 4/3
Answer:
so both tables are proportional
1. in the green table
y divided by x =
1/5 for each row
2. in the blue table
y divided by x =
2/5 for each row
Step-by-step explanation:
/ means divided by
divide y by x
for both tables
in each table
if y divided by x
show the same number
for every row
then its proportional
1. in the green table
y divided by x =
1/5 for each row
2. in the blue table
y divided by x =
2/5 for each row
so both tables are proportional