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pickupchik [31]
3 years ago
13

Solar Innovations Corporation bought a machine at the beginning of the year at a cost of $28,000. The estimated useful life was

five years and the residual value was $3,000. Assume that the estimated productive life of the machine is 10,000 units. Expected annual production was year 1, 1,900 units; year 2, 2,900 units; year 3, 1,900 units; year 4, 1,900 units; and year 5, 1,400 units. Required: Complete a depreciation schedule for each of the alternative methods. a. Straight-line. b. Units-of-production. c. Double-declining-balance. Which method will result in the highest net income in year 2
Business
1 answer:
jeyben [28]3 years ago
6 0

Answer:

You get the highest net income in year 2 with  <u>Units-of-production  method.</u>

Explanation:

Schedule of depreciation expense, accumulated depreciation, and book value per year for the equipment under the three depreciation methods is attached.  

<u>Straight-line </u>

Depreciation expense 2nd year=$5.000=(Original Value -Residual Value)/Useful life

<u>Units-of-production </u>

Units of Production Rate=2.5=(Original Value -Residual Value)/estimated productive life

Depreciation expense 2nd year= 7250

<u> Double-declining-balance. </u>

Depreciation rate        20,00%        1/useful life *100

Depreciation expense 2nd year= 6720

Download xlsx
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Jerry Jay is the CEO of Jerry's Jackets (JJ). In June, Jerry expects to produce and sell 3200 jackets, and he expects his June u
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Answer: $10240

Explanation:

Based on the information that have been provided in the question, the planning budget for the utilities in June will be calculated as:

= Fixed expenses + (Budgeted activity × Variable cost per unit)

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3 0
2 years ago
You plan to save $2,400 a year and earn an average rate of interest of 5.6 percent. How much more will your savings be worth at
mixas84 [53]

Answer:

If the deposits are made at the beginning of the year, the future value will increase by $18,821.1.-

Explanation:

Giving the following information:

Annual deposit= $2,400

Interest rate= 5.6%

Number of periods= 40

<u>First, we will calculate the future value when the deposits are made at the end:</u>

FV= {A*[(1+i)^n-1]}/i

A= annual deposit

FV= {2,400*[(1.056^40) - 1]} / 0.056

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<u>Now, if the deposits are made at the beginning:</u>

FV= {A*[(1+i)^n-1]}/i + {[A*(1+i)^n]-A}

FV= 336,091.14 + [(2,400*1.056^40) - 2,400]

FV= 336,091.14 + 18,821.10

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Difference= 354,912.24 - 336,091.14

Difference= $18,821.1

If the deposits are made at the beginning of the year, the future value will increase by $18,821.1.-

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