1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
antiseptic1488 [7]
3 years ago
10

Can anyone help please

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
8 0

A-4b that’s my answer hope this help

You might be interested in
Give the sum in simplest form: a/c + b/c = _____
djverab [1.8K]

Answer:

(a+b)/c

Step-by-step explanation:

a/c+b/c

since they have the same denominator you can add the numerator together

(a+b)/c

6 0
3 years ago
Ardem collected data from a class survey. He then randomly selected samples of five responses to generate four samples.
scoundrel [369]

Solution: The sample mean of sample 1 is:

\bar{x}=\frac{4+5+2+4+3}{5}= \frac{18}{5}=3.6

The sample mean of sample 2 is:

\bar{x}=\frac{2+2+6+5+7}{5}= \frac{22}{5}=4.4

The sample mean of sample 3 is:

\bar{x}=\frac{4+6+3+4+1}{5}= \frac{18}{5}=3.6

The sample mean of sample 4 is:

\bar{x}=\frac{5+2+4+3+6}{5}= \frac{20}{5}=4

The minimum sample mean of the four sample means is 3.6 and maximum sample mean of the four sample means is 4.4.

Therefore, using  his four samples, between 3.6 and 4.4 will Ardem's actual population mean lie.

Hence the option 3.6 and 4.4 is correct

6 0
3 years ago
Read 2 more answers
Find the equation of the circle: b with center (5, 1/4 ), radius 6
PolarNik [594]

The equation of the circle would be

(

x

−

(

−

4

)

)

2

+

(

y

−

7

)

2

=

6

2

or

(

x

+

4

)

2

+

(

y

−

7

)

2

=

36

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=if%20%5C%3A%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%29%5E%7B6%7D%20%20%5Ctimes%20%28%20%5Cfrac%7B16%7
zhenek [66]

Answer:

2

Step-by-step explanation:

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{x+2}

\frac{3^6}{4^6} \cdot \frac{16^5}{9^5}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{4^6} \cdot \frac{(4^2)^5}{(3^2)^5}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{4^6} \cdot \frac{4^{10}}{3^{10}}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{3^{10}} \cdot \frac{4^{10}}{4^6}=\frac{4^{x+2}}{3^{x+2}}

3^{-4} \cdot 4^{4}=4^{x+2}3^{-(x+2)}

This implies

x+2=4

and

-(x+2)=-4.

x+2=4 implies x=2 since subtract 2 on both sides gives us x=2.

Solving -(x+2)=-4 should give us the same value.

Multiply both sides by -1:

x+2=4

It is the same equation as the other.

You will get x=2 either way.

Let's check:

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{2+2}

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{4}

Put both sides into your calculator and see if you get the same thing on both sides:

Left hand side gives 256/81.

Right hand side gives 256/81.

Both side are indeed the same for x=2.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%28m%20%2B%2010%29%20-%202%28m%20-%20n%29%20%20%5C%3A%20what%20%5C%3A%20is%20%5C%3A%20the%20%
Umnica [9.8K]

Answer:

5m+30+2n

Step-by-step explanation:

3m+30 and - 2m+2n

5m+30+2n

8 0
3 years ago
Other questions:
  • If h has an inverse funtion and h^-1 (4) = 2 , find h(-2)<br><br> Please help Thanks!
    14·1 answer
  • Which of the following is written in scientific notation correctly?
    6·1 answer
  • In △PKQ, PK = KQ = 12, m∠P = 35º. Find PQ.
    11·1 answer
  • Y = -2/3x+ 4<br> IN STANDARD FORM
    5·2 answers
  • Help lol i need gthe answer to this everytime i do it i get it wrong
    13·1 answer
  • Monica has been saving her spare change. So far she has saved 40 coins for a total of $6.25. Some of the coins are quarters (25
    15·1 answer
  • What way of warming up is preferred before exercise? *
    8·2 answers
  • Hope u help me pls I love u
    14·1 answer
  • 15 दिइएको चित्रमा, चक्रिय चतुर्भुज ABCD का भुजाहरूER Fमा भेट्नेगरी लम्ब्याइएको छ। यदि
    14·1 answer
  • Which of the following expressions can be used to calculate the perimeter of a square with side length 5 inches?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!