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3 years ago

15

Some help with this please :3

1 answer:

tankabanditka [31]3 years ago

5 0

A=15
and a square has the same lengths
so ... x = both length and width

x^2=15
x=3.87

the question is asking for perimeter so...
3.87×4= 15.5
or
3.87+3.87+3.87+3.87= 15.5

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The monomial is a perfect cube is $\rm 343p^6q^{21}r^6$ .

<h3>Perfect cubes;</h3>

Perfect cubes are the numbers that are the triple product of the same number.

We have to determine

Which monomial is a perfect cube?

A perfect cube monomial must have three identical roots, such that the product of the roots equals the perfect square monomial.

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A perfect cube monomial must have exponents on the variables.

Then

The monomial is a perfect cube is;

$\rm= 343p^6q^{21}r^6\\\\= \sqrt[3]{ 343 }= 7$

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Let n denotes numerator and d denotes denominator of the fraction.

Given : The ratio of the numerator to the denominator of a fraction is 2 to 3.

That is $\frac{n}{d}=\frac{2}{3}$

Cross multiply , we get,

$3n=2d$

Or, $3n-2d=0$ ........(1)

Also, given : . If both the numerator and the denominator are increased by 2, the fraction becomes 3/4

That is $\frac{n+2}{d+2}=\frac{3}{4}$

Cross multiply , We get,

$4{n+2}={3}{d+2}$

$4n+8=3d+6$ .........(2)

$3d-4n=2$ .......(3)

Thus, from (1) and (2) , option (B) follows.

Solving equation (1) and (3) to get the original fraction using elimination method,

3n - 2d = 0 ............(1)

and 3d - 4n = 2 .........(3)

Multiply equation (1) by 3 , we get ,

9n - 6d = 0 ..........(4)

Multiply equation (3) by 2 , we get ,

-8n + 6d = 4 ..........(5)

Adding (4) and (5) , we get,

9n - 6d -8n + 6d = 4 + 0

⇒ n = 4

Put n = 4 in (1), we get

3n - 2d = 0 ⇒ 3(4) - 2d = 0 ⇒ 12 -2d = 0 ⇒ 12 = 2d ⇒ d = 6

so, the numerator is 4 and the denominator is 6.

Thus, the fraction is $\frac{4}{6}$

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2 years ago