Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
1) Yes
2) 5 minutes
3) 2 minutes
Step-by-step explanation:
1: Yes because, using the vertical line test, the line will cut the graph once meaning that the graph will form a function
2: 5 minutes because the horizontal line represents that she rested, therefore she was at the park for five minutes
3: 2 minutes because she traveled and reached home between 6 and 8 minutes
Y= y1
replace the y1 with the ordinate ( the y-part) of the point you are going thru
example a horizontal line going through the point (7,12) would be y=12
