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Allushta [10]
3 years ago
9

$4,000 invested in Fund A returned 5% profit. Amount invested in Fund B returned a 2% profit. How much was invested in Fund B if

both funds returned 4%?
Mathematics
1 answer:
kobusy [5.1K]3 years ago
8 0

as I read it, what I get is that

x = returned profits or yielded interest from investment in A

y = returned profits or yielded interest from investment in B

T = total amount invested or namely  A + B.

4000 were invested in A, and it yielded 5%, what's 5% of 4000? (5/100)(4000) = 200 = x.

we know the total amount is T, since A get 4000, B must have gotten T - 4000, or the slack.  We also know that B yielded a 2% profit, well, what's 2% of T - 4000?  (2/100)(T-4000) = y.

we also know that, whatever "x" and "y" are, their sum total yielded a 4% returns from T, or the total principal, what's 4% of T?  (4/100)T = 0.04T.

\bf \begin{cases} T=\textit{total principal}\\[-0.5em] \hrulefill\\ A=4000\\ x = \stackrel{\textit{5\% of A}}{200}\\[-0.5em] \hrulefill\\ B=T-4000\\ y=\stackrel{\textit{2\% of B}}{0.02(T-4000)} \end{cases} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{5\% of A}}{200}+\stackrel{\textit{2\% of B}}{0.02(T-4000)}~~=~~\stackrel{\textit{4\% of T}}{0.04T} \\\\\\ 200+0.02T-80=0.04T\implies 120+0.02T=0.04T\implies 120=0.02T \\\\\\ \cfrac{120}{0.02}=T\implies 6000=T~\hfill \stackrel{~\hfill \textit{invested in B}}{6000-4000\implies 2000}

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The difference between (3x+6y)(3x+6y) and  (4x+9y)(4x+9y) is 7x² +36xy+45y²

<h3>What is an Expression ?</h3>

An expression is a mathematical statement which has variables , constants and mathematical operators  simultaneously.

The expression given in the question is

(3x+6y)(3x+6y) and  (4x+9y)(4x+9y)

the difference when (3x+6y)(3x+6y) is subtracted from (4x+9y)(4x+9y)

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7x² +36xy+45y²

Therefore in simplest term , The difference between (3x+6y)(3x+6y) and  (4x+9y)(4x+9y) is 7x² +36xy+45y²

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