You have to solve 3 equations pretty much simultaneously here using the x and y values in the general form of the quadratic equation
Start with the first values of x=0 and y=5.1 to solve for c:
so c = 5.1
Next use the second x and y values along with the value of c in the next equation:
gives you
-2.07 = a + b. Solve this for a:
a = -2.07 - b
Finally use the third set of numbers with the c value AND the subbed value for a:
1.17 = 9(-2.07 - b)+ 3b + 5.1 which simplifies to:
1.17 = -18.63 - 9b + 3b + 5.1 which further simplifies to:
14.7 = -6b and b = -2.45
Now you have c and b, let's find a using one of the simplified equations:
-2.07 = a + b
-2.07 = a - 2.45
a = .38
So here's your equation:
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
The answer is 0 > 34, or No Solution to be exact. use the picture above as the appropriate symbol for No Solution.
She is incorrect, her statement comes with no solution.