Help - confusion :( The oxidation of copper(I) oxide, Cu2O(s), to copper(II) oxide, CuO(s), is an exothermic process,
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This is the answer for the question above:
In order to solve this, first use stoichiometry for the energy in kJ released by, converting grams of CuO2 to moles:
<span>56.96g*(1 mole/143.09 g)=0.41904 moles of Cu2O </span>
<span>2 moles of Cu2O=-292.0kJ Convert 0.41904 moles of Cu2O to kJ. </span>
<span>Finally, solve for kJ: </span>
<span>0.41904 moles of Cu2O*(-292.0kJ/2 moles of Cu2O)=-61.18 kJ of energy released</span>
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