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kipiarov [429]
3 years ago
13

What is 0.045 rounded to the nearest hundredth?

Chemistry
2 answers:
deff fn [24]3 years ago
5 0
0.05 is the answer to your question
IrinaVladis [17]3 years ago
4 0

<em>0.05 would be your answer</em> because when rounding there is one major rule which is look one place to the right for the rounding digit 5. Round up if that number is greater than or equal to 5 and round down if it is less than 5.

Therefor your answer would be 0.05.

* Hopefully this clarify everything and answers your question. Mark me the brainliest:)!!

<em>∞ 234483279c20∞</em>

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A 25.00 mL sample of 0.320 M KOH is titrated with 0.750 M HBr at 25 °C.
Fudgin [204]

Answer:

a. pH = 13.50

b. pH = 13.15

Explanation:

Hello!

In this case, since the undergoing chemical reaction between KOH and HBr is:

HBr+KOH\rightarrow KBr+H_2O

As they are both strong. In such a way, since the initial analyte is the 25.00 mL solution of 0.320-M KOH, we first compute the pOH it has, considering that all the KOH is ionized in potassium and hydroxide ions:

pOH=-log([OH^-])=-log(0.320)=0.50

Thus, the pH is:

pH+pOH=14\\pH=14-pOH=14-0.50\\pH=13.50

Which is the same answer for a and b as they ask the same.

Moreover, once 5.00 mL of the HBr is added, we need to compute the reacting moles of each substance:

n_{KOH}=0.02500mL*0.320mol/L=0.00800mol\\\\n_{HBr}=0.005L*0.750mol/L=0.00375mol

It means that since there are more moles of KOH, we need to compute the remaining moles after those 0.00375 moles of acid consume 0.00375 moles of base because they are in a 1:1 mole ratio:

n_{KOH}^{remaining}=0.00425mol

Next, we compute the resulting concentration of hydroxide ions (equal to the concentration of KOH) in the final solution of 30.00 mL (25.00 mL + 5.00 mL):

[OH^-]=[KOH]=\frac{0.00425mol}{0.03000L}=0.142M

So the pOH and the pH turn out:

pOH=-log(0.142)=0.849\\pH+pOH=14\\pH=14-pOH=14-0.849\\pH=13.15

Best regards!

7 0
3 years ago
Which of the following is a major difference between lactic acid and alcohol fermentation?
pishuonlain [190]

Both lactic acid and alcoholic fermentation begin with pyruvic acid and nadh. they are anaerobic processes that result in the production of energy in the absence of oxygen. So basically the two differences are that one makes ethanol and one makes lactic acid, and the other is that they are made by different species.


Alcohol fermentation requires aerobic conditions, while lactic acid fermentation requires anaerobic conditions.

6 0
3 years ago
What is AgNO3 + KCI-KNO3+AgCI. What type of reaction does this represent
PIT_PIT [208]
<span>C4H10 + 6.5 O2 ----> 4CO2 + 5H2O 

2C4H10 + 13 O2 ----> 8CO2 + 10H2O 

1. Count the C on the left (4), put a 4 where the C on the right. 

2. Count the H on the left (1), you have two on the right, so you multimply this two by 5. Put the 5 in front of the H2O 

3. Count the O on the right. You have 4*2 + 5 = 13. You have two on the left, so you need 6.5 on the left. 

4. Now multiply everything on the equation by two so you have nice integer numbers. 

5. check you have the same amount of everything on each side. 
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6 0
3 years ago
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Sphinxa [80]

D represents ion-dipole forces that are stronger than the force C.

Explanation:

D represents the ion-dipole force.

C represents the H-bonding forces.

ion-dipole force is a force that is due to electrostatic attraction and has a dipole between an ion and a neutral molecule.

It is electrostatic in nature.

A hydrogen bond is the force between the hydrogen with the electro negative atom of one molecule, to electro negative atom of some other molecule. such as: O, F, N

Ion dipole force is stronger than the H-bonding.

3 0
3 years ago
Which factors must be equal when a reversible chemical process reaches equilibrium?
Anon25 [30]
The concentration of the reactants and products remain constant. Because the rates of the forward and reverse reaction are equal there is no net change to the amount of reactants or products produced.May 19, 2011
3 0
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