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3 years ago

The density of a metal cube is 8 x103 kg/m3. Convert

Chemistry

1 answer:

Rom4ik [11]3 years ago

4 0

Answer:

Explanation:

[peirod4

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Mixtures can be separated into their components by taking advantage of differences in the chemical properties of the components.

Sedaia [141]

The method of separating mixtures by means of their differences in the chemical properties of the components is less convenient because these methods requires reactions therefore needs energy, increasing the costs for the process.

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3 years ago

Last question<br> help<br> im confusion

Andrej [43]

Remark

The given thing on the right is a positron. The mass for these subatomic particles is considered to be 0. It's atomic number is 1 which means it is a blood relative of a proton.

So essentially what happens is that X is one space to the left on the periodic table. But let's solve this a little bit more formally.

Solution

$_{65}^{147}\text{Tb}\longrightarrow _{z}^{y}\text{x} +_{1}^{0}{e}$

y stays the same at 147. It is z that changes.

65 = z + 1 Subtract 1 from both sides.

64 = z

So the chemical with 64 as its position on the periodic table is

Gadolinium and the answer is C

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3 years ago

How many neutrons are found in a stable isotope of uranium-235?

bezimeni [28]

thx but it's actually 143

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2 years ago

Urea, CH4N2O (s), is manufactured from NH3 (g) and CO2 (g). H2O (l) is another product of this reaction. An experiment is starte

Katarina [22]

Answer:

a. 4.41 g of Urea

b. 1.5 g of Urea

Explanation:

To start the problem, we define the reaction:

2NH₃ (g) + CO₂ (g) → CH₄N₂O (s) + H₂O(l)

We only have mass of ammonia, so we assume the carbon dioxide is in excess and ammonia is the limiting reactant:

2.6 g . 1mol / 17g = 0.153 moles of ammonia

Ratio is 2:1. 2 moles of ammonia can produce 1 mol of urea

0.153 moles ammonia may produce, the half of moles

0153 /2 = 0.076 moles of urea

To state the theoretical yield we convert moles to mass:

0.076 mol . 58 g/mol = 4.41 g

That's the 100 % yield reaction

If the percent yield, was 34%:

4.41 g . 0.34 = 1.50 g of urea were produced.

Formula is (Yield produced / Theoretical yield) . 100 → Percent yield

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2 years ago

Help meeeeehahahshshs

natka813 [3]

What grade are you in I’m in 9th ;-;

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2 years ago