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CaHeK987 [17]
3 years ago
8

Helppp with these 2 questions sorry.

Chemistry
1 answer:
Nataly_w [17]3 years ago
7 0

Answer:

Can i be Branliest

Explanation:

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How many molecules are in 1 mol of the chemical equation shown above
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There's 6.022×10^23 particles in 1 mole of anything

like there is 1000 grams in 1 kilogram of anything
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Carbon is black, crystalline and hard. Oxygen alone is a gas. How does the substance that is formed when these two elements comb
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Carbon oxides (monoxide, dioxide) are gases :)
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Which substance is a pure substance? <br> Cereal <br> Silver <br> Jelly bean <br> Shampoo
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Fun FACT : An apple, potato, and onion all taste the same if you eat them with your nose plugged

6 0
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A student uses a solution of 1.2 molar sodium hydroxide (NaOH) to calculate the concentration of a solution of sulfuric acid (H2
Mila [183]

From the calculations, the concentration of the acid is 0.24 M.

<h3>What is neutralization?</h3>

The term neutralization has to do with a reaction in which an acid and a base react to form salt and water only.

We have to use the formula;

CAVA/CBVB = NA/NB

CAVANB =CBVBNA

The equation of the reaction is; 2NaOH + H2SO4 ----> Na2SO4 + 2H2O

CA = ?

CB = 1.2 M

VA =  50 mL

VB = 20 mL

NA = 1

NB = 2

CA = CBVBNA/VANB

CA = 1.2 M * 20 mL * 1/ 50 mL * 2

CA = 0.24 M

Learn more about neutralization:brainly.com/question/27891712

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5 0
2 years ago
A 52.0 mL portion of a 1.20 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
RoseWind [281]

Answer:

C_3=0.125M

Explanation:

Hello!

In this case, we can divide the problem in two steps:

1. Dilution to 278 mL: here, the initial concentration and volume are 1.20 M and 52.0 mL respectively, and a final volume of 278 mL, it means that the moles remain the same so we can write:

V_1C_1=V_2C_2

So we solve for C2:

C_2=\frac{C_1V_1}{V_2}=\frac{52.0mL*1.20M}{278mL}\\\\C_2=0.224M

2. Now, since 111 mL of water is added, we compute the final volume, V3:

V_3=139+111=250mL

So, the final concentration of the 139 mL portion is:

C_3=\frac{139 mL*0.224M}{250mL}\\\\C_3=0.125M

Best regards!

8 0
3 years ago
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