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3 years ago

9

Solve the given inequality√4x-4+8≤5

1 answer:

vodka [1.7K]3 years ago

4 0

Step-by-step explanation:

$\sqrt{4} x \leqslant 5 - 8 + 4$
$\sqrt{4} x \leqslant 1$
$x = \frac{1}{ \sqrt{4} }$

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