Im sorry really dont know the answer
Since it is stated that it is an ideal gas, we use the ideal gas equation to solve the volume of this gas sample. The ideal gas equation is expressed as:
PV = nRT
V = nRT / P
V = 0.200 (8.314) (400) / 200x10^3
V = 3.33 x 10^-3 m³ or 3.33L
Therefore, the correct answer is option B.
Answer:
23.46 mmHg is the vapor pressure for the solution
Explanation:
To solve this problem we need to apply a colligative property, which is the lowering vapor pressure.
The formula for this is: P°- P' = P° . Xm
where P' is vapor pressure for solution and P°, vapor pressure for pure solvent.
Let's determine the Xm (mole fraction for solute)
We calculate the moles of the solute and the solvent and we sum each other:
Moles of solute: 60 g /342 g/mol = 0.175 moles of sucrose
Moles of solvent: 250 g / 18 g/mol = 13.8 moles of water
Total moles: 13.8 moles + 0.175 moles = 13.975 moles
Xm for solute: 0.175 moles / 13.975 moles = 0.0125
Let's replace data in the formula: 23.76 mmHg - P' = 23.76 mmHg . 0.0125
P' = - (23.76 mmHg . 0.0125 - 23.76 mmHg) → 23.46 mmHg
It classify living organisms by2characteristics
Answer:
Mass FeCl2 = 0.0333g
Mass CrCl2 = 0.9961g
Explanation:
To solve this problem. The first equation we can write is:
Mass FeCl2 + Mass CrCl2 = 1.0294g <em>(1)</em>
Now, the Chlorides of FeCl2 and CrCl2 react producing 2.3609g of AgCl
Using molar mass of these species (126.75g/mol, 122.9g/mol, 143.32g/mol, respectively), you can write the equation:
2Mass FeCl2 / 126.75 + 2Mass CrCl2 / 122.9 = 2.3609/143.32
<em>That is: Moles Chloride before = Moles Chloride in AgCl after reaction</em>
7.8895x10⁻³Mass FeCl2 + 0.0162734MassCrCl2 = 0.016473 <em>(2)</em>
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Replacing (1) in (2):
7.8895x10⁻³ (1.0294g - MassCrCl2) + 0.0162734MassCrCl2 = 0.016473
8.12145x10⁻³ -7.8895x10⁻³MassCrCl2 + 0.0162734Mass CrCl2 = 0.016473
8.3839x10⁻³ MassCrCl2 = 8.35155x10⁻³
Mass CrCl2 = 0.9961g
And:
Mass FeCl2 = 1.0294g - 0.9961g
Mass FeCl2 = 0.0333g
