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BARSIC [14]
2 years ago
12

PLEASE I NEED HELP!!! I WILL MARK YOU AS BRAINLEST!!!!

Chemistry
1 answer:
posledela2 years ago
7 0

Answer:

  1. hayop ka tang INA ka <em><u /></em><em><u /></em><em><u /></em><em><u /></em>
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If you prepared a 3.25 M solution of sucrose (molar mass 342 g/mole) ,
Dafna11 [192]

Answer:

a. 0.8125 moles of sucrose

b. 277.8 g of sucrose

Explanation:

Consider these relation's value:

Molarity = Mol / Volume(L)

Mol = Molarity . Volume(L)

Volume(L) = Mol / Molarity

So, Molarity = 3.25M

Volume(L) = 0.25L

Molarity . Volume(L) = Mol → 3.25mol/L . 0.25L = 0.8125 mol

Let's convert the moles to mass → 0.8125 mol . 342 g /1mol = 277.8 g of sucrose

7 0
3 years ago
Read 2 more answers
Many popular beverages are sold in two-kilo bottles. true or false
Molodets [167]
False. The answer is liter. kilo is the base (liter) times 1000. it would make no sense.
5 0
3 years ago
Compute diffusion coefficients for the interdiffusion of carbon in both (a) α-iron (BCC) and (b) γ-iron (FCC) at 800.˚C. Assume
Ne4ueva [31]

Answer:

a)1.404 E-10 m^2/s

b)1.438 E-12 m^2/s

Explanation:

Diffusion Coefficients can be calculated at different temperatures taking into account the energy of the diffusive process, remember that this process takes place in the interstices of the solid, and gets with higher temperatures due to the higher kinetic energy of the particles.

D=D_{o} *exp(-Q/RT)

a) For α-iron (BCC)

D=1.10*10^{-6} m^{2}/s *exp(-80.0kJ/mol/8.314*10^{-3}kJ/mol*k*1073.15K)= 1.404*10^{-10} m^{2}/s

b) For γ-iron (FCC)

D=2.30*10^{-5} m^{2}/s *exp(-148.0kJ/mol/8.314*10^{-3}kJ/mol*k*1073.15K)= 1.438*10^{-12} m^{2}/s

5 0
3 years ago
The average kinetic energy of water molecules is greatest in which of these samples?(1) 10 g of water at 35°C(2) 10 g of water a
Ipatiy [6.2K]
The question asks about the average kinetic energy so it is not related with mass. We only need to compare the temperature. The higher temperature is, the higher kinetic energy is. So the answer is (2).
3 0
3 years ago
Read 2 more answers
How many moles are equal to 89.23g of calcium oxide, CaO?
Katen [24]

1.59moles

Explanation:

Mass  of CaO = 89.23g

Unknown

Number of moles = ?

Solution:

The mole is a unit of measurement in chemistry used to delineate the number of particles an atom contains.

A mole of a substance contains the avogadro's number of particles.

Number of moles = \frac{mass}{molar mass}

Molar mass of CaO = 40 + 16 = 56g/mol

  Number of moles = \frac{89.23}{56} = 1.59moles

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

8 0
2 years ago
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