Answer:
Ch4 Is an ion so the molecule yes 5
Explanation:
Sry for bad Engish me polish
464 g radioisotope was present when the sample was put in storage
<h3>Further explanation</h3>
Given
Sample waste of Co-60 = 14.5 g
26.5 years in storage
Required
Initial sample
Solution
General formulas used in decay:
![\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cboxed%7B%5Cbold%7BN_t%3DN_0%28%5Cdfrac%7B1%7D%7B2%7D%29%5E%7Bt%2Ft%5Cfrac%7B1%7D%7B2%7D%20%7D%7D%7D)
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
Half-life of Co-60 = 5.3 years
Input the value :
![\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}](https://tex.z-dn.net/?f=%5Ctt%2014.5%3DNo.%5Cdfrac%7B1%7D%7B2%7D%5E%7B26.5%2F5.3%7D%5C%5C%5C%5C14.5%3DNo.%5Cdfrac%7B1%7D%7B2%7D%5E5%5C%5C%5C%5CNo%3D%5Cboxed%7B%5Cbold%7B464~g%7D%7D)
For example...
You have solution with [H+] = 0,01M
>>>> pH = -log[H+] = -log0,01 = 2
And you increase the [H+] by 10x ---> 0,01×10 = 0,1M
>>>> pH = -log0,1 = 1
○ pH decrease by 2x
○ pH is more acidic
Answer:
answer is A. a saturated hydrocarbon that has more than 35 carbons in its chain
Explanation:
edge in 2020 :)
<span>LiOH+HBr---> LiBr +h20. Moles of LiOH = 10/24 = 0.41moles. According to stoichiometry, moles of LiOH = moles of LiBr = 0.41moles. Therefore mass of LiBr =moles of LiBr x molecular weight of LiBr = o.41 x 87 = 35.67g. Hope it helps </span>