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IceJOKER [234]
3 years ago
6

In the reaction shown above , the?

Chemistry
1 answer:
matrenka [14]3 years ago
8 0

Answer:

I think option (d) is right answer

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Using table 9.4, calculate an approximate enthalpy (in kj) for the reaction of 1.02 g gaseous methanol (ch3oh) in excess molecul
Tanya [424]

<u>Given:</u>

Mass of methanol = 1.02 g

<u>To determine:</u>

Enthalpy for the reaction of 1.02 g of methanol with excess O2

<u>Explanation:</u>

Balanced equation-

2CH3OH(g) + 3O2(g) → 2CO2(g) + 4H2O(g)

The reaction enthalpy is given as:

ΔHrxn = ∑nH°f(products) - ∑nH°f(reactants)

where n = number of moles

H°f = standard enthalpy of formation.

ΔHrxn = [2H°f(CO2(g)) + 4H°f(H2O(g))] - [2H°f(CH3OH(g)) + 3H°f(O2(g))]

           = [2(-393.5) + 4(-241.8)]-[2(-201.5) + 3(0)] = -1351.2 kJ

Now, 1 mole of CH3OH = 32 g

The calculated ΔHrxn corresponds to 2 moles of CH3OH. i.e.

The enthalpy change for 64 g of Ch3OH = -1351.2 kJ

Therefore, for 1.02g gaseous methanol we have:

ΔH = 1.02 * -1351.2/64 = -21.5 kJ

Ans: The enthalpy for the given reaction is -21.5 kJ



6 0
3 years ago
How many moles are there in 40g of calcium
drek231 [11]
40 grams ÷ 40.08 grams/moles = 1 mole
8 0
3 years ago
I NEED HELP PLEASE, THANKS!! :)
In-s [12.5K]

Answer:

B) microscopic

Explanation:

A scanning tunneling microscope allows imaging of microscopic particles.

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H2O2; hydrogen peroxide,

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