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3 years ago

A 1500 kg car is moving 18 m/s how much force is required to bring the car to a stop in 12 seconds

Physics

1 answer:

Marat540 [252]3 years ago

3 0

Answer:

2250N

Explanation:

F = Mv/t

Force F =?

Mass M = 1500kg

Velocity v = 18m/s

Time T = 12 secs

Therefore

F = 1500 x 18 /12

Multiply through

F = 27000/12

F = 2250N

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4 years ago

A distance-time graph indicates that an object 100 m in 4s and then remains at rest for 6s what is the average speed of the obje

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The average speed is 10 m/s.

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The motion of the object is divided into two parts.

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4 years ago

Find the speed at which Superman (mass=78.0 kg) must fly into a train (mass = 17863 kg) traveling at 75.0 km/hr to stop it. Runn

lapo4ka [179]

Answer with Explanation:

We are given that

Mass of superman=m=78 kg

Mass of train=m'=17863 kg

Speed of train=u'=75 km/h= $75\times \frac{5}{18}=20.8 m/s$

$1 km/h=\frac{5}{18} m/s$

Let initial speed of superman=u

Momentum=mv

Using the formula

$78u=17863\times 75$

$u=\frac{17863\times 75}{78}$

$u=17175.9 km/h$

Average horizontal force=0.58

Deceleration $a=-0.58\times 9.8=-5.68 m/s^2$

Final speed of train=v'=0

$v=u+at$

Using the formula

$0=20.8-5.68t$

$5.68t=20.8$

$t=\frac{v'-u'}{a}=\frac{0-20.8}{-5.68}$

$t=3.66 s$

$v^2-u^2=2as$

Using the formula

$0-(20.8)^2=2(-5.68)a$

$(20.8)^2=2(5.68)s$

$s={\frac{(20.8)^2}{2(5.68)}=38.1 m$

6 0

3 years ago

Read 2 more answers