Using law of conservation of energy, "Energy can neither be created nor be destroyed but it can be transformed from one form to another".
That is, sum of Kinetic energy and Potential energy at initial point is equal to the sum of Kinetic energy and Potential energy at final point.
We can say that,
(K.E)1 + (P.E.)1 = (K.E)2 + (P.E)2
1/2 m1 * v1² + m1*g*h1 = 1/2 m2 * v2² + m2* g*h2
For motion in circular path,
Initial velocity v1 is at h1 =0
Final velocity v2 is at h2= d
For rotational motion, inertia is denoted by I.
1/2 I1 * v1² = 1/2 I2* v2² + I2 gd
1/2 I2*v2² = 1/2 I1*v1²- I2 gd
v2²= I1/I2 * v1²- 2 gd
v2= √(I1/12* v1²- 2gd)
The above equation gives the speed of the ball when it reaches the top of circular path in term of I, g and d.
Mac and Keena are experimenting with pulses on a rope. Mac vibrates one end up and down while Keena holds the other end. This creates a pulse which they observe moving from end to end. How does the position of a point on the rope before the start of the pulse compare to its position after the pulse passes? Explain your reasoning.
Answer:
The bikers speed at the top of other hill is <u>25.82 m/s.</u>
Explanation:
Considering the biker is riding on a frictionless surface.
∴ There is no non-conservative or external force acting on the biker.
Hence we can conserve the energy of biker and bike as a system.
Let,
= 44m
= 10m
Since the biker starts from rest , his initial speed = 0 m/s
Let final speed of the bike at the top of other hill be .
∴ Initial Energy (at the top of 44m hill) =
Final Energy (at the top of 10m hill) = .
Conserving both the energies , we get
=
∴
Substituting the values for g , , , we get
= 25.82 m/s
Answer:
Uniform circular motion is one in which an object moves in a circular path at constant speed.
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I hope this helps! Have an amazing day!
The correct answer is D...