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Answer:
(a). The acceleration due to gravity at the surface of Titania is 0.37 m/s².
(b). The average density of Titania is 1656.47 kg/m³
Explanation:
Given that,
Radius of Titania 
Mass of Titania 
We need to calculate the acceleration due to gravity at the surface of Titania
Using formula of the acceleration due to gravity on earth
The acceleration due to gravity on Titania
Put the value into the formula
The acceleration due to gravity at the surface of Titania is 0.37 m/s².
(b). We assume Titania is a sphere
The average density of the earth is 5500 kg/m³.
We need to calculate the average density of Titania
Using formula of density
The average density of Titania is 1656.47 kg/m³
Hence, (a). The acceleration due to gravity at the surface of Titania is 0.37 m/s².
(b). The average density of Titania is 1656.47 kg/m³
Answer:
The answer should be C
Explanation:
An exothermic process releases heat, causing the temperature of the immediate surroundings to rise. An endothermic process absorbs heat and cools the surroundings.
Please tell me if it is wrong
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Answer:
Option B
Explanation:
=> Current = Voltage / Resistance
I = V/R
1. For the first resistor: I = 40/100
I = 0.4 A
2. For the second resistor: I = 40/360
I = 0.11 A
