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andrew11 [14]
2 years ago
8

Order -12,|-25|,-10,18, |29|,and 5 from greatest to least It's a little more difficult

Mathematics
2 answers:
yanalaym [24]2 years ago
6 0
29, 18, 5, -10, -12, -25

Hope this helped :)
VashaNatasha [74]2 years ago
5 0
29, 18, 5, -10, -12, -25
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(?,3) is on the line y=2x+5 what is the other coordinate
Dmitriy789 [7]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Substitute it into the equation:

3 = 2x + 5

Subtract 5 from both sides:

-2 = 2x

Divide both sides by 2:

x = -1

The other coordinate is -1

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0
3 years ago
Read 2 more answers
-25+t=-44 solve using addition principle. The solution is t=
love history [14]

Explanation:

First, add by 25 both sides of an equation.

-25+t+25=-44+25

Then, simplify by equation and add/subtract by the numbers.

44-25=19

*The answer must be have a negative sign.

\boxed{t=-19}

Hope this helps!

Thank you!

Have a great day!

3 0
2 years ago
Read 2 more answers
Differentiate the function with respect to x<br> f(x)= x^4/ x^2- 4<br> Show work
jeyben [28]

Answer:

Step-by-step explanation:

f(x)=\frac{u}{v} ,u~ and~ v~ functions~ of~ x\\f'(x)=\frac{v ~u'-u~v' }{v^2} \\f(x)=\frac{x^4}{x^2-4} \\f'(x)=\frac{(x^2-4)*4x^3-x^4(2x)}{(x^2-4)^2} \\=\frac{2x^3(2x^2-8-x^2) }{(x^2-4)^2} \\=\frac{2x^3(x^2-8)}{(x^2-4)^2}

7 0
2 years ago
PQ=11 and QR =10 what is PR
a_sh-v [17]

Step-by-step explanation:

I have no idea good luck love

6 0
3 years ago
Use diagrams or the description of equivalent ratios to show thay 2:3,4:6, and 8:12 are equivalent
VikaD [51]
So
lets say we have
a/b=2a/2b
we know that if we invert one and multiply it by the other (divide them), we get 1 because a/a=1 where a=a

so
2/3 and 4/6 are equivelent because if you divide them we get 12/12=1

2/3 and 8/12 are equivilent because if you divide them we get 24/24=1

and sinde 2/3=4/6 and 2/3=8/12, 2/3=4/6=8/12

they are equivlent
6 0
2 years ago
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