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3 years ago

Simplify the following expression -5[(x^3+1)(x+4)]

Mathematics

1 answer:

katrin [286]3 years ago

4 0

Answer:

Step-by-step explanation:

-5[ (x³+1)(x+4) ] = -5[ x³*(x+4) + 1*(x+4) ]

= -5 [ x³*x + x³*4 + 1*x + 1*4 ]

= -5 [ x⁴ + 4x³ + x + 4]

= -5*x⁴ + (-5)*4x³ + (-5)*x + (-5) * 4

= -5x⁴ - 20x³ - 5x - 20

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The sum of the diagonals of a rhombus is 5√2.

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Greetings!
Let ABCD be a rhombus
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Area of ABCD = Ar△ABD + Ar △BCD
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In △AOB, we have
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Square rooting both sides
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