Simplify the following expression -5[(x^3+1)(x+4)]
1 answer:
Answer:
B
Step-by-step explanation:
-5[ (x³+1)(x+4) ] = -5[ x³*(x+4) + 1*(x+4) ]
= -5 [ x³*x + x³*4 + 1*x + 1*4 ]
= -5 [ x⁴ + 4x³ + x + 4]
= -5*x⁴ + (-5)*4x³ + (-5)*x + (-5) * 4
= -5x⁴ - 20x³ - 5x - 20
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Answer=
y=-3+3
y=0
the sum of -3+3 is zero.
Here ya go answer down below
Answer:
I assume your goal is to rationalize the denominator -
So you need to multiply the denominator by its conjugate.
So we have:
->
gg
Answer:
B
Step-by-step explanation:
Answer:
Answer C
Step-by-step explanation:
