UGRENT!!!!! PLEASE HELP!!!!!!!

Which prime number do the prime factorization of 130 and 165 have in common?

Marizza181 [45]

Answer:

They both have the #5 and they both have 3 #'s that are prime?

Step-by-step explanation:

5 0

3 years ago

Find the area of the polygon shown. Enter the number into the box.

lord [1]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the image of the polygon is not given.

I will answer this question with the attached image (similar to your question)

The attached polygon is a trapezoid of the following dimensions.

$Height = 4ft$

<u>Parallel sides</u>

$Side\ 1 = 4ft$

$Side\ 2 = 4ft+1ft = 5ft$

So, the area is:

$Area = \frac{1}{2} * (Side\ 1 + Side\ 2) * Height$

$Area = \frac{1}{2} * (4ft + 5ft) * 4ft$

$Area = \frac{1}{2} * 9ft * 4ft$

$Area = 18ft^2$

6 0

3 years ago

Jylene and her brother had a total of $35.19 to buy school supplies. Jylene's school supplies cost

cricket20 [7]

Answer:

13.31

Step-by-step explanation:

First do 35.19-12.78=22.41

I assume slightly more than $9 is .1

then subtract 22.41-9.1=13.31

5 0

3 years ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

7 0

3 years ago

3(x-1) - 8 = 4(1+x) +5. Too hard, i keep getting confused

svet-max [94.6K]

3(x-1)-8=4(1+x)+5

One solution was found :

x = -20

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

3*(x-1)-8-(4*(1+x)+5)=0

Step by step solution :

Step 1 :

Equation at the end of step 1 :

((3•(x-1))-8)-(4•(x+1)+5) = 0

Step 2 :

Equation at the end of step 2 :

(3 • (x - 1) - 8) - (4x + 9) = 0

Step 3 :

Step 4 :

Pulling out like terms :

4.1 Pull out like factors :

-x - 20 = -1 • (x + 20)

Equation at the end of step 4 :

-x - 20 = 0

Step 5 :

Solving a Single Variable Equation :

5.1 Solve : -x-20 = 0

Add 20 to both sides of the equation :

-x = 20

Multiply both sides of the equation by (-1) : x = -20

One solution was found :

x = -20

hope this is wht u wanted

4 0

3 years ago