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Len [333]
3 years ago
10

What is digital graphics?

Computers and Technology
2 answers:
densk [106]3 years ago
7 0

Answer:

1) its what they use to make things

2)to make things like dinosaurs

3) it makes these things look real

Explanation:

muminat3 years ago
5 0

Answer:

-<u>Digital graphics combine text and images to produce a graphic product which cane used for s specific purpose. By using both writing and images they can present an idea or a message in an eye-catching and effective way. They can be printed or used onscreen.</u>

-<u>Digital graphics can simply be produce to entertain people.</u>

-The graphics included in multimedia or game products are also obvious examples of graphics designed to entertain. Part of entertaining can be <u>to grab the attention of potential readers so that they are more likely to think about buying the product.</u>

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When preparing the heading for an MLA Format Academic Report, which of the following shows the proper order of the for lines of
Sloan [31]

Answer:

A. Student Name, Instructor, Course, Date

Explanation:

Begin one inch from the top of the first page and flush with the left margin. Type your name, your instructor's name, the course number, and the date on separate lines, using double spaces between each. Double space once more and center the title

3 0
3 years ago
A 1024-bit message is sent that contains 992 data bits and 32 CRC bits. CRC is computed using the IEEE 802 standardized, 32-degr
Studentka2010 [4]

Answer:

a) Yes

b) Yes

c) Yes

d) No

e) Yes

f) No

Explanation:

a) All single-bit errors  are caught by Cyclic Redundancy Check (CRC) and it produces 100 % of error detection.

b) All double-bit errors for any reasonably long message  are caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.

c) 5 isolated bit errors  are not caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit since CRC may not be able to catch all even numbers of isolated bit errors so it is not even.

It produces nearly 100 % of error detection.

d) All even numbers of isolated bit errors may not be caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.

e) All burst errors with burst lengths less than or equal to 32 are caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.

f) A burst error with burst length greater than 32 may not be caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit.

Cyclic Redundancy Check (CRC) does not detect the length of error burst which is greater than or equal to r bits.

4 0
3 years ago
What is telepresence
Vitek1552 [10]
The use of virtual reality technology, especially for remote control of machinery or for apparent participation in distant events.
7 0
3 years ago
Hello everyone can help me give all the answer​
krek1111 [17]

Answer:

1. were

2. were

3 was

4 was

5 were

1 wasnt

2 werent

3werent

4 wasnt

5 werent

were you at work?

was it in the garden?

were they worried?

was lucy present?

were his friends late?

1 they were

2 it was

3 he wasn't

4 I was

5 they weren't

Explanation:

7 0
3 years ago
1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
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