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Len [333]
4 years ago
10

What is digital graphics?

Computers and Technology
2 answers:
densk [106]4 years ago
7 0

Answer:

1) its what they use to make things

2)to make things like dinosaurs

3) it makes these things look real

Explanation:

muminat4 years ago
5 0

Answer:

-<u>Digital graphics combine text and images to produce a graphic product which cane used for s specific purpose. By using both writing and images they can present an idea or a message in an eye-catching and effective way. They can be printed or used onscreen.</u>

-<u>Digital graphics can simply be produce to entertain people.</u>

-The graphics included in multimedia or game products are also obvious examples of graphics designed to entertain. Part of entertaining can be <u>to grab the attention of potential readers so that they are more likely to think about buying the product.</u>

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When a person devises the idea for the venture, develops a business plan, uses savings or loans to acquire other resources and a
krok68 [10]

That person is acting as an entrepreneur.

explanation because an entrepreneur is someone who organizes and operates a business , taking on greater than normal financial risks in order to have a high rate of return

8 0
3 years ago
Write a recursive method to return the number of uppercase letters in a String. You need to define the following two methods. Th
satela [25.4K]

Answer:

<u>Recursive function with two parameters that return the number of uppercase letters in a String</u>

public static int count(String str,int h)//Defining function

{

      if(str.charAt(0)>='A' && str.charAt(0)<='Z')//Checking the characters from A to Z

{

          h++; //incrementing the counter

          if(str.length()>=2){

              return count(str.substring(1),h);//recalling function

          }

      }

      if(str.length()>=2){

              return count(str.substring(1),h); //recalling function

      }

      return h;

  }

This is the recursive function with the name count of return type integer,having parameters str of string type and h of integer type.In this we are checking the characters at a particular position from A to Z.

<u>Recursive function with one parameter that return the number of uppercase letters in a String</u>

public static int count(String str)//Defining function

{

      if(str.charAt(0)>='A' && str.charAt(0)<='Z')//Checking the characters from A to Z

{

          count++; //incrementing the counter

          if(str.length()>=2){

              return count(str.substring(1));//recalling function

          }

      }

      if(str.length()>=2){

              return count(str.substring(1)); //recalling function

      }

      return count;

  }

This is the recursive function with the name count of return type integer,having parameters str of string type .In this we are checking the characters at a particular position from A to Z.

<u>Java program that return the number of uppercase letters in a String</u>

import java.util.*;

public class Myjava{

static int count =0;//Defining globally  

 

public static int count(String str,int h)//Defining function

{

      if(str.charAt(0)>='A' && str.charAt(0)<='Z')//Checking the characters from A to Z

{

          h++;

//incrementing the counter

          if(str.length()>=2){

              return count(str.substring(1),h);//recalling function

          }

      }

      if(str.length()>=2){

              return count(str.substring(1),h);

//recalling function

      }

      return h;

 

  }

  public static void main(String[] args)//driver function

  {

      System.out.println("Enter a string");//taking input

      Scanner scan = new Scanner(System.in);

      String s = scan.nextLine();

      int h =0;

      System.out.println("Counting the Uppercase letters: "+count(s,h));

  }

}

<u>Output</u>

Enter a string  WolFIE

Counting the Uppercase letters: 4

4 0
3 years ago
A teacher uses the spreadsheet below to determine the average quiz score of each student. The teacher inserts this information i
Vinvika [58]

need help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

6 0
4 years ago
Read 2 more answers
Design a class named largeIntegers such that an object of this class can store an integer of any number of digits. Add operation
SpyIntel [72]

Answer:

Here the code is given as follows,

Explanation:

Code:

import java.util.Scanner;

//created class named largeintegers

class largeintegers{

   //class can hold a long number

   long number;

   //constructor to set number

  largeintegers(long number){

      this.number=number;

  }

  //getNumber method to get number

  long getNumber(){

      return number;

  }

  //below are some basic operations

  long addition(long num1,long num2){

       return num1+num2;

   }

   long subtract(long num1,long num2){

       return num1-num2;

   }

   long multiply(long num1,long num2){

       return num1*num2;

   }

   boolean compare(long num1,long num2)

   {

       return num1>num2;

   }

  public static void main(String[] args) {

      //declared to long numbers

      long number1,number2;

      //scanner class to take user input

      Scanner sc= new Scanner(System.in);

      //taking input numbers

      System.out.println("Enter a Number ");

      number1=sc.nextLong();

      System.out.println("Enter 2nd Number :");

      number2=sc.nextLong();

      //created two objects

      largeintegers object=new largeintegers(number1);

      largeintegers object2=new largeintegers(number2);

      //displaying two numbers

      System.out.println("Entered Numbers ");

      System.out.println(object.getNumber());

      System.out.println(object2.getNumber());

      //calling basic methods using created objects

      System.out.println("Some Operations on Given two Numbers ");

      System.out.println("Addition:"+object.addition(object.getNumber(), object2.getNumber()));

      System.out.println("Subtraction:"+object.subtract(object.getNumber(), object2.getNumber()));

      System.out.println("Multiplication:"+object.multiply(object.getNumber(), object2.getNumber()));

      System.out.println("Comparison:");

      if(object.compare(object.getNumber(), object2.getNumber())==true)

      {

          System.out.println("First Number is Greater than Second Number ");

      }

      else

      {

          System.out.println("Second Number is Greater than First Number ");

      }

      sc.close();

  }

}

Output:-

6 0
3 years ago
1. Implement the function dict_intersect, which takes two dictionaries as parameters d1 and d2, and returns a new dictionary whi
stich3 [128]

Answer:

1  

def dict_intersect(d1,d2): #create dictionary

  d3={} #dictionaries

  for key1,value1 in d1.items():       #iterate through the loop  

      if key1 in d2:   #checking condition

          d3[key1]=(d1[key1],d2[key1])   #add the items into the dictionary  

  return d 3

print(dict_intersect({'a': 'apple', 'b': 'banana'}, {'b': 'bee', 'c': 'cat'})) #display

2

def consolidate(*l1):  #create consolidate

  d3={} # create dictionary

  for k in l1:       #iterate through the loop

      for number in k:   #iterate through  the loop                               d3[number]=d3.get(number,0)+1   #increment the value

             return d 3 #return

print(consolidate([1,2,3], [1,1,1], [2,4], [1])) #display

Explanation:

1

Following are  the description of program

  • Create a dictionary i.e"dict_intersect(d1,d2) "   in this dictionary created a dictionary d3 .
  • After that iterated the loop and check the condition .
  • If the condition is true then add the items into the dictionary and return the dictionary d3 .
  • Finally print them that are specified in the given question .

2

Following are  the description of program

  • Create a dictionary  consolidate inside that created a dictionary "d3" .
  • After that iterated the loop outer as well as inner loop and increment the value of items .
  • Return the d3 dictionary and print the dictionary as specified in the given question .

5 0
4 years ago
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