the fat car has a lot to pass on PC Dell is the only thing to
Answer:
Conflicts can be classified into five different types: structural, value, relationship, interest, and data [
Explanation:
Answer:
Follows are the solution to this question:
Explanation:
The process ID is not static because this can't be used to identity, therefore, it includes excellent service providers like HTTP since it is allocated dynamically only to process whenever a process is initiated.
Sometimes its instance connectors are managed on numerous TSAPs. This can be implemented unless the process ID is being used as each procedure could have an identity.
Answer:
scanf("%d %lf %c", &age, &pay, §ion);
Explanation:
To read the value in c program, the instruction scanf is used.
To read the integer value, use the %d format specifier in the scanf and corresponding variable name age with ampersand operator.
To read the double value, use the %lf format specifier in the scanf and corresponding variable name pay with ampersand operator.
To read the character value, use the %c format specifier in the scanf and corresponding variable name section with ampersand operator.
Answer:
hope this helps and do consider giving a brainliest to the ans if it helped.
Explanation:
//program to check if the entered grid is magic square or not
/**c++ standard libraries
*/
#include<bits/stdc++.h>
using namespace std;
/**function to check whether the entered grid is magic square or not
*/
int isMagicSquare(int arr[3][3]){
int i,j,sum=0,sum1=0,rsum,csum;
for(i=0;i<3;i++){
sum+=arr[i][i];
sum1+=arr[i][2-i];
}
if(sum!=sum1){
return 0;
}
for(i=0;i<3;i++){
rsum=0;
csum=0;
for(j=0;j<3;j++){
rsum+=arr[i][j];
csum+=arr[j][i];
}
if(sum!=rsum){
return 0;
}
if(sum!=csum){
return 0;
}
}
return 1;
}
/** main function to get user entries and
* call function
* and print output
*/
int main(){
int i,j,arr[3][3]={0};
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cout<<"Enter the number for row "<<i<<" and column "<<j<<" : ";
cin>>arr[i][j];
}
}
int ret = isMagicSquare(arr);
if(ret==1){
cout<<"This is a Lo Shu magic square"<<endl;
}
else{
cout<<"This is not a Lo Shu magic square"<<endl;
}
return 0;
}
