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3 years ago

Rajesh is working out the area of a circle with radius 10 he writes

Mathematics

1 answer:

Maru [420]3 years ago

7 0

Answer:

He multiplied the radius by 2 instead of squaring it

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Need to find the ratio

wolverine [178]

Answer:

Step-by-step explanation:

CosA = AB/AC = 12/20 = 3/5

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3 years ago

A rectangular fence is 27.8 meters by 34.2 meters.what is its the perimeter answer

storchak [24]

The perimeter of a rectangle is calculated as

Perimeter= 2(length + breadth )

So, Perimeter = 2*length + 2*breadth

Now we are given the length as 34.2 meters and breadth as 27.8 meters

So the perimeter will be

2(34.2+27.8) meters

$(2*34.2) + (2*27.8)$

which equals 2(62) meters

Hence Perimeter = 124 meters

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3 years ago

83 simplified whoever gets it right is the brainliest

Alina [70]

83 is a whole number and cannot be simplified.

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3 years ago

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Domain and range and function or not

aksik [14]

Answer:

Domain: -2,0,1,3,4

Range: 2,3

Yes its a function

Step-by-step explanation:

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3 years ago

Find the curl of ~V ~V = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

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3 years ago