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My name is Ann [436]
3 years ago
8

Ben uses a compass and straightedge to bisect segment PQ, as shown: segment PQ with compass open to greater than half of segment

PQ Which statement best explains why Ben must open the compass to a width greater than half of segment PQ? To be able to create two intersecting arcs above and below the line segment To be able to create arcs above the line segment To find the length of the line segment To find the length of half of the line segment
Mathematics
1 answer:
il63 [147K]3 years ago
7 0

Answer: To be able to create two intersecting arcs above and below the line segment

Step-by-step explanation:

That is one of the steps to bisecting a line segment lol

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In geometry, Heron's formula (sometimes called Hero's formula), named after Hero of Alexandria, gives the area of a triangle by
uysha [10]

Answer:

C) 6.495\: ft^2

Step-by-step explanation:

a = 7 ft, b = 3 ft, c = 5 ft (Given)

Therefore, a + b + c = 7 + 3 + 5 = 15 ft

Let's calculate semi Perimeter of the triangle which is given by s

s =\frac{a+b+c}{2}=\frac{15}{2} = 7.5 \: ft

Now, by Heron's formula, area of triangle ABC is given as:

A(\triangle ABC) =\sqrt{s(s-a) (s-b)(s-c)}

\therefore A(\triangle ABC) =\sqrt{7.5(7.5-7) (7.5-3)(7.5-5)}

\therefore A(\triangle ABC) =\sqrt{7.5(0.5) (4.5)(2.5)}

\therefore A(\triangle ABC) =\sqrt{42.1875}

\therefore A(\triangle ABC) =6.49519053

\therefore A(\triangle ABC) =6.495\: ft^2

8 0
3 years ago
1/4(9-12)+1/3(9+9) please ohh please can you help on this It's final exam for high school
Nina [5.8K]
21/4 is the answer your welcome
4 0
3 years ago
Rewire the rational exponent as a radical
Mice21 [21]

Answer:

\large\boxed{\sqrt[3]{\left(\dfrac{15}{4}\right)^2}}

Step-by-step explanation:

a^\frac{n}{m}=\sqrt[m]{a^n}\\---------------------\\\\\left(5\times\dfrac{3}{4}\right)^\frac{2}{3}=\left(\dfrac{5\times3}{4}\right)^\frac{2}{3}=\left(\dfrac{15}{4}\right)^\frac{2}{3}=\sqrt[3]{\left(\dfrac{15}{4}\right)^2}

Answer:

\large\boxed{C.\ \sqrt5}

Step-by-step explanation:

\left(5^\frac{3}{4}\right)^\frac{2}{3}\\\\\text{Use}\ (a^n)^m=a^{nm}\\\\5^{\frac{3}{4}\cdot\frac{2}{3}}=5^{\frac{1}{2}\cdot\frac{1}{1}}=5^\frac{1}{2}=\sqrt[2]5=\sqrt5

5 0
3 years ago
Find the 1st term of a sequence if the common difference = -2 and the 13th term =59
Marat540 [252]

Answer:

83

Step-by-step explanation:

<u>Formula for 13th term:</u>

t(13) = a + 12d, where a- first term, d- common difference

<u>Given</u>

  • t(13) = 59
  • d = -2
  • a = ?

<u>As per the formula for 13th term:</u>

  • 59 = a + 12*(-2)
  • 59 = a - 24
  • a = 59 + 24
  • a = 83
8 0
3 years ago
(10 + 3x) = 5x<br> Solve please
yanalaym [24]

Answer:

x=5

Step-by-step explanation:

10 +3x = 5x

Subtract 3x from each side

10+3x-3x= 5x-3x

10 =2x

Divide each side by 2

10/2 = 2x/2

5 =x

8 0
3 years ago
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