(10 elements..........) 2^(10)<span>=<span>1024
</span></span><span>A discrete set with n elements has 2^n subsets. 2^n=1024 implies there are n=10 elements in this set. Any subset with 0 through n-1 elements is a proper subset of the set, as in each of those cases there exists at least one element of the set that is not in the subset, which is the requirement to be a proper subset. Therefore, we have 1023 proper subsets.</span>
Answer:
-25 is the correct answer
Step-by-step explanation:
hope this helps:)
2n + 1 , 2n + 3 , 2n + 5
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( 2n + 5 ) + ( 2n + 3 ) = 5 × ( 2n + 1 ) - 15
4n + 8 = 10n + 5 - 15
4n + 8 = 10n - 10
Add both sides 10
4n + 8 + 10 = 10n - 10 + 10
4n + 18 = 10n
Subtract both sides 4n
4n - 4n + 18 = 10n - 4n
18 = 6n
Divide both sides by 6
18 ÷ 6 = 6n ÷ 6
n = 3
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Thus that three numbers are :
2(3) + 1 , 2(3) + 3 , 2(3) + 5
6 + 1 , 6 + 3 , 6 + 5
7 , 9 , 11
And we're done ....
<span>10x+y=19
when x = 10:
substitute with x=10 into the equation given:
10(10) + y = 19
or:
100 + y = 19
bring 100 to the other side to be -100
y = 19 - 100
y = -81
That's it
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