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balu736 [363]
3 years ago
8

Is gasoline a solution

Chemistry
1 answer:
Stolb23 [73]3 years ago
8 0
I would say that gas is a solution and milk, coke and paint are heterogeneous. If you churn milk butter will emerge and the milk will be left. Paint is made of different types of particles in the mixture. Coke is a solution of sugar water, plus CO2, where the gas emerges from the solution.
Gasoline is the same throughout.
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If a sample of copper is 215g, how many moles of copper atoms are in the sample?
shusha [124]

Answer:

3.38 moles.

Explanation:

The following data were obtained from the question:

Mass of copper (Cu) = 215 g

Number of mole of copper (Cu) =...?

The number of mole of copper (Cu) in 215 g can be obtained as follow:

Mass of copper (Cu) = 215 g

Molar mass of copper (Cu) = 63.55 g/mol

Number of mole of copper (Cu) =...?

Mole = mass /Molar mass

Mole of Cu = 215/63.55

Mole of Cu = 3.38 moles

Therefore, 3.38 moles of copper (Cu) is present in the sample.

6 0
4 years ago
Scientific theories might be rejected because there is not yet enough information to explain the evidence supporting them. True
Oksanka [162]
True.

Hope this helps!
8 0
3 years ago
Read 2 more answers
Part 1)
pav-90 [236]

Answer:

1.69×10²⁹ molecules.

Explanation:

The following data were obtained from the question:

Mass of Ammonia (NH3) = 5.25 tons

Molecules of Ammonia (NH3) =.?

Next, we shall convert 5.25 tons to grams (g). This can be obtained as follow:

1 ton = 907184.74 g

Therefore,

5.25 ton = 5.25 ton × 907184.74 g / 1 ton

5.25 ton = 4762719.885 g

Therefore, 5.25 tons is equivalent to 4762719.885 g

Finally, we shall determine the number of molecules of ammonia, NH3 in 4762719.885 g. This can be obtained as follow:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of ammonia, NH3 also contains 6.02×10²³ molecules.

1 mole of ammonia, NH3 = 14 + (3x1) = 14 + 3 = 17 g

17 g of ammonia, NH3 contains 6.02×10²³ molecules.

Therefore, 4762719.885 g of ammonia, NH3 will contain = (4762719.885 × 6.02×10²³) / 17 = 1.69×10²⁹ molecules.

From the calculations made above,

5.25 tons (4762719.885 g) of ammonia, NH3 contains 1.69×10²⁹ molecules.

4 0
3 years ago
Reactivity and flammability are are examples of properties.​
nika2105 [10]

Answer:

they are eamples of chemical properties

Explanation:

flammibility is the chemical makeup of the element that makes it flamable and reactivitie is the chemical makeup of an element that is able to reacte to another element

3 0
3 years ago
For most solids at room temperature, the specific heat is determined by oscillations of the atom cores in the lattice (each osci
Cloud [144]

Answer:

The specific heat of copper is  C= 392 J/kg\cdot ^o K

Explanation:

From the question we are told that

The amount of energy contributed by each oscillating lattice site  is  E =3 kT

       The atomic mass of copper  is  M =  63.6 g/mol

        The atomic mass of aluminum is  m_a = 27.0g/mol

        The specific heat of aluminum is  c_a = 900 J/kg-K

 The objective of this solution is to obtain the specific heat of copper

       Now specific heat can be  defined as the heat required to raise the temperature of  1 kg of a substance by  1 ^o K

  The general equation for specific heat is  

                    C = \frac{dU}{dT}

Where dT is the change in temperature

             dU is the change in internal energy

The internal energy is mathematically evaluated as

                       U = 3nk_BT

      Where  k_B is the Boltzmann constant with a value of 1.38*10^{-23} kg \cdot m^2 /s^2 \cdot ^o K

                    T is the room temperature

                      n is the number of atoms in a substance

Generally number of  atoms in mass of an element can be obtained using the mathematical operation

                      n = \frac{m}{M}  * N_A

Where N_A is the Avogadro's number with a constant value of  6.022*10^{23} /  mol

          M is the atomic mass of the element

           m actual mass of the element

  So the number of atoms in 1 kg of copper is evaluated as  

             m = 1 kg = 1 kg *  \frac{10000 g}{1kg }  = 1000g

The number of atom is  

                       n = \frac{1000}{63.6} * (6.0*0^{23})

                          = 9.46*10^{24} \ atoms

Now substituting the equation for internal energy into the equation for specific heat

          C = \frac{d}{dT} (3 n k_B T)

              =3nk_B

Substituting values

         C = 3 (9.46*10^{24} )(1.38 *10^{-23})

            C= 392 J/kg\cdot ^o K

5 0
3 years ago
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