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solong [7]
3 years ago
11

One molecule of the spherically shaped, oxygen‑carrying protein in red blood cells, hemoglobin, has a diameter of 5.5 nm 5.5 nm

. What is this diameter in meters?
Chemistry
1 answer:
horrorfan [7]3 years ago
6 0

Answer : The diameter in meters is, 5.5\times 10^{-9}m

Explanation :

As we are given that the diameter of red blood cells is, 5.5 nm. Now we have to convert it into meter.

The conversion used from nanometer to meter is:

1nm=10^{-9}m

As, 1nm=10^{-9}m

So, 5.5nm=\frac{5.5nm}{1nm}\times 10^{-9}m=5.5\times 10^{-9}m

Thus, the diameter in meters is, 5.5\times 10^{-9}m

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Claire is investigating potential and kinetic energy using a large ball. For her investigation, Claire will stand at the top of
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The ball's potential energy will decrease, and its kinetic energy will increase.

Explanation:

The ball's potential energy will decrease down the slope and its kinetic energy will increase.

Kinetic energy is the energy due to the motion of a body.

 K. E = \frac{1}{2} m v²

 m is the mass of the ball

  v is the velocity of the ball.

Potential energy is the energy due to the motion of a body down slope.

It is expressed as:

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   g is the acceleration due to gravity of the body

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We can see as the body drops down the slope, the height diminishes and the velocity increases.

learn more:

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3 0
3 years ago
A sample of pure sodium-24 has an initial mass of 10.0 grams. How many grams of sodium-24 will remain at the end of 4 half-lives
astra-53 [7]
I got b 5)A sample of pure sodium-24 has an initial mass of 10.0 grams. How many grams of sodium-24 will remain at the end of 4 half-lives?


A. 0.315
B. 0.630
C. 5.00
D. 6.00
8 0
3 years ago
What is a decay series?
denpristay [2]

Answer:

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5 0
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Technically speaking, in terms of chemistry and physics, steam is visible and can be seen.
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3 years ago
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What volume of O2(
irakobra [83]
Answer is: volume of oxygen is 4.63 liters.
Balanced chemical reaction: 2C + O₂ → 2CO.
m(C) = 4.50 g.
n(C) = m(C) ÷ M(C).
n(C) = 4.50 g ÷ 12 g/mol.
n(C) = 0.375 mol.
From chemical reaction: n(C) : n(O₂) = 2 : 1.
n(O₂) = 0.1875 mol.
T = 48°C = 321.15 K.
p = 810 mmHg ÷ 760 mmHg/atm= 1.066 atm.
<span>R = 0.08206 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.</span>
V(O₂) = n·R·T / p.<span>
V(O₂) = 0.1875 mol · 0.08206 L·atm/mol·K · 321.15 K / 1.066 atm.</span><span>
V(O₂<span>) = 4.63 L.</span></span>
4 0
3 years ago
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