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Hunter-Best [27]
3 years ago
6

Reactivity and flammability are are examples of properties.​

Chemistry
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

they are eamples of chemical properties

Explanation:

flammibility is the chemical makeup of the element that makes it flamable and reactivitie is the chemical makeup of an element that is able to reacte to another element

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A student increases the temperature of a 417cm³ balloon from 278k to 231k. Assuming constant pressure, what should the new volum
viva [34]
Charles law states that volume of gas is directly proportional to temperature at constant pressure 
V/T = k
where V - volume , T - temperature and k - constant
\frac{V1}{T1} =  \frac{V2}{T2}
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 

in the question it states that the temperature has been increased from 278 K to 231 K but it should actually be temperature is decreased from 278 K to 308 K
substituting the values in the equation 
\frac{417cm^{3} }{278K} =  \frac{V}{308 K}
V = 462 cm³
the answer should be D. 462 cm³ 
3 0
3 years ago
What are the empirical formula and empirical formula mass for C10H30O10?
AysviL [449]

Answer:

Empirical formula: CH₃O

Empirical formula mass = 31 g/mol

Explanation:

Data Given:

Molecular Formula = C₁₀H₃₀O₁₀

Empirical Formula = ?

Empirical Formula mass =

Solution

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

The ratio of the molecular formula should be divided by whole number to get the simplest ratio of molecule

As

C₁₀H₃₀O₁₀ Consist of  10 Carbon (C) atoms, 30 Hydrogen (H) atoms, and 10 Oxygen (O) atoms.

Now

Look at the ratio of these three atoms in the compound

                         C : H : O

                        10 : 30 : 10

Divide the ratio by two to get simplest ratio

                          C      :   H      :    O

                         10/10 : 30/10 : 10/10

                             1 : 3 : 1

So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1

So the empirical formula will be

                     Empirical formula of C₁₀H₃₀O₁₀ =  CH₃O

Now

To find the empirical formula mass in g/mol

Formula mass:

Formula mass is the total sum of the atomic masses of all the atoms present in a formula unit.

**Note:

if we represent the molar mass of the empirical formula for one mol in grams then it is written as g/mol

So,

As the empirical formula of C₁₀H₃₀O₁₀ is CH₃O

Then Its empirical formula mass will be

CH₃O

Atomic Mass of C = 12

Atomic Mass of H = 3

Atomic Mass of O = 16

Total Molar mass of CH₃O

CH₃O = 12 + 3(1) + 16

CH₃O = 12 + 3 + 16

CH₃O = 31 g/mol

4 0
2 years ago
The mass of a 50-mL volumetric flask is 40.638 g. After adding 15.0 mL of 95% ethanol and adding enough water to complete the vo
Nuetrik [128]

Answer

0.9516 grams / mL (50.00 has 4 sig digs.)

Remark

You have a couple of extraneous numbers there. You don't care about anything except the mass of the flask +  water/alcohol mixture  (88.219 grams). and the mass of the flask (40.638 grams)

Formulas

  • mass water/alcohol mixture = mass of the flask with fluid - mass flask
  • density = mass / volume

Solution

mass water/alcohol mixture = 88.219 - 40.638 = 47.581

  • Volume = 50 mL
  • Density = mass / Volume
  • Density = 47.581/50
  • Density = 0.95162  There are 4 sig digs so the answer should be
  • 0.9516
3 0
3 years ago
A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
DaniilM [7]
800 joules because it's twice the amount
7 0
3 years ago
Read 2 more answers
Why are metals good conductors of heat?
loris [4]

Answer: A. The free-moving electrons transmit heat quickly.

Explanation:

3 0
2 years ago
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