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Olegator [25]
4 years ago
5

I NEED HELP!!!!!!!!!!!!!!!!

Chemistry
1 answer:
sergij07 [2.7K]4 years ago
8 0
A is the correct answer
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Do free electrons appear anywhere in the balanced equation for a redox reaction?
Andru [333]

Yes, free electrons appear in balanced redox reaction equations. However, this is only true for half-reactions. This is because redox reactions primarily involve the transfer of electrons, which are better visualized if explicitly shown in the balanced reactions. In reduction reactions, electrons are placed on the left side of the equation. Oxidation reactions show electrons on the right side of the equation.


Explanation:

A half reaction is either the chemical reaction or reduction reaction part of an oxidoreduction reaction. A half reaction is obtained by considering the amendment in chemical reaction states of individual substances concerned within the oxidoreduction reaction. Half-reactions are usually used as a way of leveling oxidoreduction reactions.The half-reaction on the anode, wherever chemical reaction happens, is Zn(s) = Zn2+ (aq) + (2e-).

The metal loses 2 electrons to create Zn2+. The half-reaction on the cathode wherever reduction happens is Cu2+ (aq) + 2e- = Cu(s).

Here, the copper ions gain electrons and become solid copper.

4 0
3 years ago
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The number of electrons in atoms can change when elements combine to form
Nutka1998 [239]
It can change in C. compounds to change when elements combine that will form 
8 0
3 years ago
Where do producers belong on the food chain?
Akimi4 [234]
The bottom of the food chain
4 0
3 years ago
I need the answer to this asap!! please explain
kumpel [21]

Answer:

See explanation

Explanation:

Calcium carbide reacts with water to yield acetylene gas and calcium hydroxide as follows;

CaC2(s)+2H2O(g)⇋Ca(OH)2(s)+C2H2(g)

This now shows us that the equation as written in the question is wrong. Since the equation for the reaction of calcium carbide and water as shown in the question is wrong, the equation can not be balanced.

6 0
3 years ago
A sample of 0.300 mol of a metal m reacts completely with excess fluorine to form 23.4 g of mf2. what element is represented by
Phoenix [80]

Molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.

Given,

Moles of metal M = 0.300 moles

 weight of mF₂ formed =23.4g

we have to find the name of element m...

Now,

 m + F₂ → mF₂

1 mole of m reacts with 1 mole of F₂ (or 2 molecule of flourine) to form 1 mole of mF₂

Hence,

 0.300 moles of m reacts with 0.300 moles of F₂ to form 0.300 moles of mF₂.

 

Hence,

 23.4 g = 0.300 moles of mf2

0.300 × 38g + 0.300 × m = 23.4 g

Hence

 m = 40 g

So, molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.

 Thus, from the above conclusion we can say that, name of element m is Calcium. which is represented by the symbol Ca.

Learn more about Calcium here:brainly.com/question/26636816

#SPJ4

5 0
1 year ago
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