Answer:
Atom: The smallest particle of an element that has the properties of the element and can exist either alone or in combination.
Particle: One of the very small parts of matter (as a molecule, atom, or electron)
Kinetic: Of or relating to the motions of material bodies and the forces and energy associated with them
Explanation:
Answer:
Im sorry i cant write a whole essay right now but these sourcea could help.
https://climate.nasa.gov/effects/
https://www.climate.gov/news-features/understanding-climate/climate-change-global-temperature
Answer: V= 4.2L
Explanation: To solve for the new volume we use Boyle's Law.
P1V1 = P2V2
Derive for V2 the new volume.
V2 = P1V1 / P2
V2 = 1.8 atm x 2.8 L / 1.2 atm
= 4.2 L
Answer:
1200 mL
Explanation:
Given data
- Initial pressure (P₁): 600.0 mmHg
- Initial volume (V₁): 400.0 mL
- Final pressure (P₂): 200.0 mmHg
For a gaseous sample, there is an inverse relationship between the pressure and the volume. If we consider the gas as an ideal gas, we can find the final volume using Boyle's law.
<h3>
Answer:</h3>
120.1 g CH₃COOH
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
1.204 × 10²⁴ molecules CH₃COOH
<u>Step 2: Identify Conversions</u>
Avogadro's Number
[PT] Molar Mass of C - 12.01 g/mol
[PT] Molar Mass of H - 1.01 g/mol
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of CH₃COOH - 12.01 + 3(1.01) + 12.01 + 16.00 + 16.00 + 1.01 = 60.06 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 4 sig figs.</em>
120.08 g CH₃COOH ≈ 120.1 g CH₃COOH