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3 years ago

Which situation can be solved by the equation 1.24×3.5=x?

Mathematics

1 answer:

WARRIOR [948]3 years ago

5 0

Answer:

Andrea bought 3.5 pounds of bananas for a total of $1.24. What was the cost per pound of the bananas?

Step-by-step explanation:

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Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .

6 0

3 years ago

What is 1+1 . i apparently have to write 20 characters so here they are

Liula [17]

Answer:

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

An electric bulb is sold in a box measuring 5 cm by 4 cm by 4 cm. If the shopkeeper receives them in a carton measuring 50 cm by

katen-ka-za [31]

Answer:

250

Step-by-step explanation:

Bulb box and carton both are of cuboidal shape.

For bulb box the dimensions are:

l = 5 cm, w = 4 cm, h = 4 cm

$V_{Bulb\: box} =lwh$

$\implies V_{Bulb\: box} =5(4)(4)$

$\implies V_{Bulb\: box} =80\: cm^3$

For Carton the dimensions are:

l = 50 cm, w = 20 cm, h = 20 cm

$V_{Carton} =lwh$

$\implies V_{Carton} =50(20)(20)$

$\implies V_{Bulb\: box} =20,000\: cm^3$

To find the number of bulbs packed in the carton, divide the $V_{Carton}$ by $V_{Bulb\: box}$

$Number \:of \:bulbs =\frac{V_{Carton}}{V_{Bulb\: box}}$

$\implies Number \:of \:bulbs =\frac{20,000}{80}$

$\implies Number \:of \:bulbs = 250$

So, 250 bulbs will be packed in one carton.

3 0

2 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

Answer:

3003 number of 5-member chess teams can be chosen from 15 interested players.

Step-by-step explanation:

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$