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4 years ago

Which equation would best help solve the following problem?

Mathematics

1 answer:

forsale [732]4 years ago

6 0

Your answer is <span>–4.9t^2 + 15t + 1 = 0

Hope this helps.

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Angle 1 and Angle 2 are complementary angles.

Andrej [43]

Answer:

p = 35

Step-by-step explanation:

Complementary angles sum to 90°

Sum the 2 given angles and equate to 90, that is

20 + 2p = 90 ( subtract 20 from both sides )

2p = 70 ( divide both sides by 2 )

p = 35

7 0

3 years ago

WILL GIVE BRAINLIEST!!!

Free_Kalibri [48]

The answer is B)75pounds

4 0

3 years ago

Please can anyone simplyfy that and can you tell the steps?

Leno4ka [110]

Answer:

we need an attachment we can’t see the question ma’am.

Step-by-step explanation:

6 0

3 years ago

√−100 = ___ +_____i<br> ...

Natalija [7]

Answer:

Step-by-step explanation:

Rewrite this as

$\sqrt{(-1)(100)}$

Knowing that i-squared = -1:

$\sqrt{(i^2)(100)}$

Both i-squared and 100 are perfect squares, so this simplifies to

±10i

7 0

3 years ago

Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0

Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

The general equation for the second-order polynomial is:

$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

$4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0$

$k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0$

$k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0$

$3\cdot k^{3} - 3\cdot k - 1 = 0$

7 0

3 years ago