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damaskus [11]
2 years ago
15

Solve for x in the picture below

Mathematics
1 answer:
xxMikexx [17]2 years ago
8 0

Answer:

82 degrees

Step-by-step explanation:

The sum of all angle measurements of a 7 sided polygon is 900 degrees, and the sum of all expressed degrees is 818. 900-818= 82 degrees

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Marcy left for school and felt like running. She ran for a while and then stopped to rest. After resting, she walked the rest of
egoroff_w [7]

Answer:

The last graph best represents the story

Step-by-step explanation:

Mary left for school from rest. So the initial speed is zero.

So we start from the origin and draw a straight line with a positive slope to running, that is as time increases , distance covered also increases.

When she is resting, her speed is zero so we draw a horizontal line to indicate this second phase of her journey.

After resting she still continued her journey to school.

This part also has a positive slope.

8 0
3 years ago
The vertices of triangle JKL, shown below, are J(2, 1), K(4, 4), and L(6, 2). If triangle JKL is translated 2 units to the left
julia-pushkina [17]

Answer:

L=(4,-2)

Step-by-step explanation:Left = -2 units and down = -4 units, left is x direction and down is y direction. (x,y).

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2 years ago
Someone please help me answer at least one of these problems it’s really hard and it’s due by tomorrow and I really don’t get it
Serga [27]
For 5 and 6 : 5 would be 144 when you put 3 in the position of the t . And 6 would be 1,024 when you put 8 where the t is .
5 0
3 years ago
A sneeze can travel up to 100mi/h how many feet per second is this a sneeze can travel up to 100m/h how many feet per second is
JulsSmile [24]
Ok first you have to convert 100 miles to feet.

A mile is 5,280 feet
100x5,280
528,000

Thats how much feet per hour. Now we need to find feet per second. So lets divide 528,000 by 60

528,000/60
8,800

Now we know 8,800 is how much feet per minute now we divide it once more by 60 to find feet per second.

8,800/60
146 2/3

So your answer is 146 2/3ft/sec

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3 0
3 years ago
Please help me solve this problem ASAP
DiKsa [7]

\bold{\huge{\blue{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

  • Area of square B is 144 inches²
  • Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{ Area \: of \: square =  Side × Side }

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 144 =  x × x }

\sf{ 144 =  x² }

\sf{ x = √144}

\bold{\red{ x = 12\: inches }}

Thus, The dimension of square B is 12 inches

<h3><u>Now, </u></h3>

Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 169 =  y × y }

\sf{ 169 =  y² }

\sf{ y = √169}

\bold{\green{ y = 13\: inches }}

Thus, The dimension of square C is 13 inches.

<h3><u>Now, </u></h3>

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3><u>Therefore</u><u>, </u><u>By </u><u>using </u><u>Pythagoras </u><u>theorem</u><u>, </u></h3>

  • <u>The </u><u>sum </u><u>of </u><u>squares </u><u>of </u><u>base </u><u>and </u><u>perpendicular </u><u>height </u><u>equal </u><u>to </u><u>the </u><u>square </u><u>of </u><u>hypotenuse </u>

<u>That </u><u>is</u><u>, </u>

\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}

<u>Here</u><u>, </u>

  • Base = x = 12 inches
  • Perpendicular = z
  • Hypotenuse = y = 13 inches

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ (z)² + (x)² = (y)² }

\sf{ (z)² + (12)² = (169)² }

\sf{ (z)² + 144 = 169}

\sf{ (z)² = 169 - 144 }

\sf{ (z)² = 25}

\bold{\blue{ z = 5 }}

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

Area of square

\sf{ = Side × Side }

\sf{ = 5 × 5  }

\bold{\orange{ = 25\: inches }}

Hence, The area of square A is 25 inches.

6 0
2 years ago
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