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3 years ago

Given the figure below, find the values of x and z.

Mathematics

1 answer:

charle [14.2K]3 years ago

8 0

Answer:

I think z = 89 and I don’t know x

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Which number lime shows a point that represents 25%

pychu [463]

The answer is F. I counted from the first line to the dot and said 25 the next line to the same amount of lines and so on and so forward.

8 0

4 years ago

Identify the slope from the points (1,-3) and (4,2) identify the slope for each graph

Aliun [14]

Answer:

First: 1/4

Second: 3/5

Step-by-step explanation:

FIRST:

You can easily solve this problem by creating a slope triangle between the points given.

1 up

———————- = 1/4

4 to the right

SECOND:

To solve for slope with two points, you do y1-y2/x1-x2.

1-4 -3

—— = — = 3/5

-3-2 -5

8 0

3 years ago

Which equation has the same solution as x -12 = 40

bearhunter [10]

Steps to solve:

x - 12 = 40

~Ad 12 to both sides

x = 52

Best of Luck!

4 0

4 years ago

Divide: 15m^2n + 20mn/5mn

mylen [45]

The answer is
15m^2n + 4/n
Hope that helps, have a nice night or day <4

8 0

3 years ago

A group of researchers wants to know whether men are more likely than women to contract a novel coronavirus. They surveyed two r

olasank [31]

Answer:

Test statistic Z= 0.13008 < 1.96 at 0.10 level of significance

null hypothesis is accepted

There is no difference proportion of positive tests among men is different from the proportion of positive tests among women

Step-by-step explanation:

<em>Step(I)</em>:-

Given surveyed two random samples of 390 men and 360 women who were tested

first sample proportion

$p_{1} = \frac{360}{390} = 0.9230$

second sample proportion

$p_{2} = \frac{47}{52} = 0.9038$

Step(ii):-

Null hypothesis : H₀ : There is no difference proportion of positive tests among men is different from the proportion of positive tests among women

Alternative Hypothesis:-

There is difference between proportion of positive tests among men is different from the proportion of positive tests among women

$Z = \frac{p_{1}- p_{2} }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } } }$

where

$P = \frac{n_{1}p_{1} +n_{2} p_{2} }{n_{1}+n_{2} }$

P = 0.920

$Z= \frac{0.9230-0.9038}{\sqrt{0.920 X0.08(\frac{1}{390}+\frac{1}{52} } )}$

Test statistic Z = 0.13008

Level of significance = 0.10

The critical value Z₀.₁₀ = 1.645

Test statistic Z=0.13008 < 1.645 at 0.1 level of significance

Null hypothesis is accepted

There is no difference proportion of positive tests among men is different from the proportion of positive tests among women

7 0

3 years ago