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Alla [95]
3 years ago
13

PLSSS HELP MEE

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
7 0

Answer:

c = ±n

Step-by-step explanation:

Taking the square root of both sides yields

√c² = √n² or c = ±n

c² = n² is a quadratic equation, so we expect that there will be two roots:  one positive and one negative.  

diamong [38]3 years ago
5 0

1.

c² = n²

√c² = √n²

c = n

2.

if

c = 3 + 6 = 9

and

n = 5 + 4 = 9

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3 3/4x2 4/5 simplest form
solong [7]

Answer:

The answer is 10 1/2.

Step-by-step explanation:

<u>First:</u>

Convert any mixed numbers to fractions.

Then your initial equation becomes:

15/4×14/5

<u>Next:</u>

Apply the fractions formula for multiplication,

=15/4×14/5

=210/20

<u>Last:</u>

Simplify 210/20, the answer is

=10 1/2

Hope this helped! =)

6 0
3 years ago
Rileys parents got a cell phone plan that has a $40 monthly fee for the first phone. For each extra phone, there is a $15 phone
Solnce55 [7]
Okay. So when it comes to combining like terms, they should have the same variable and power. They dont have to be the exact same number, but they should at least have the same terms. In the expression 40 + 15e + 10e, 15e and 10e both have like terms, because they have the same variable. 15e + 10e is 25e. 40 has no like term, so that is left alone. The expression simplified is 40 + 25e.
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3 years ago
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3 years ago
Read 2 more answers
Kim wants to determine a 90 percent confidence interval for the true proportion of high school students in the area who attend t
PolarNik [594]

Answer:

We need a sample of at least 752 students.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large of a sample must she have to get a margin of error less than 0.03

We need a sample of at least n students.

n is found when M = 0.03.

We have no information about the true proportion, so we use \pi = 0.5.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.645*0.5

\sqrt{n} = \frac{1.645*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.645*0.5}{0.03})^{2}

n = 751.67

Rounding up

We need a sample of at least 752 students.

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