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serg [7]
3 years ago
15

The management of a supermarket wants to adopt a new promotional policy of giving a free gift to every

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

X ≥ 112,6 $

Step-by-step explanation:

Normal Distribution  N ( 95 , 16 )

μ₀ = 95

σ  =  16

We need to get z (score) for area 0,1357; then from z - Table we get

z (score) = 1,1

Now  z (score ) = ( X - μ₀ )/σ

1,1 = ( X - 95 ) / 16

17,60 + 95  = X

X = 112,6 $

That means that in order to get a gift customes has to spend at least 112,6 $

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What is the equation of the function represented by this graph?
gayaneshka [121]

Answer:

\displaystyle g(x) = -(x + 2)(x - 4)

Step-by-step explanation:

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3 years ago
The proof that UX ≅ SV is shown. Given: △STU an equilateral triangle ∠TXU ≅ ∠TVS Prove: UX ≅ SV What is the missing statement in
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6 0
3 years ago
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La temperatura a una distancia r del centro de una lámina está dada por T=40 (r2?2r) . La variación instantánea de la temperatur
PilotLPTM [1.2K]

For this, the first thing to do is to assume that the function of temperature with respect to r is written in one of the following ways:

Way 1:

T = 40 (r ^ 2 + 2r)

Way 2:

T = 40 (r ^ 2-2r)

To find the instant variation we must find the derivative of the temperature with respect to the distance r.

We have then:

For function 1:

\frac {dT} {dr} = 40 \frac {d ((r ^ 2 + 2r))} {dr}\\

\frac {dT} {dr} = 40 (2r + 2)

Rewriting

\frac {dT} {dr} = 80r + 80

For function 2:

\frac {dT} {dr} = 40 \frac {d ((r ^ 2-2r))} {dr}

\frac {dT} {dr} = 40 (2r-2)

Rewriting

\frac {dT} {dr} = 80r-80

Answer:

The instantaneous variation of the temperature with respect to r is given by:

Assuming function 1:

\frac {dT} {dr} = 80r + 80

Assuming Function 2:

\frac {dT} {dr} = 80r-80

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3 years ago
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Answer:

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Step-by-step explanation:

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