Answer:
what the heck is that i rhink you mess up
X^2/3 = 64


it is easier to first find square root of 64 and than power it to 3
square root of 64 is 8 which means our equation now looks like:
x = 8^3
now the answer is after powering 8 to 3:
x = 512
Given:
Admission to the local movie theater is $3 for each child and $7 for each adult.
A group of 12 people pay $64 admission.
To find:
The number of children in a group.
Solution:
Let the number of children be x and number of adults be y.
According to the question,
Total persons :
...(i)
Total cost :
...(ii)
Multiply equation (i) by 7 and subtract the result from (ii).



Divide both sides by -4.

Therefore, the number of children is 5.
Answer:
If we arrange the talks from the lowest starting time to the highest ending time we get total of 11 talks.
using algorithm 7 we get answer (1) - (3) - (6) - (9) the largest number of talks scheduled.
Step-by-step explanation:
arranging the talks from lowest starting time to the highest ending time.
thus,
- 9:00 a.m. and 9:45 a.m.
- 9:30 a.m. and 10:00 a.m.
- 9:50 a.m. and 10:15 a.m.
- 10:00 a.m. and 10:30 a.m.
- 10:10 a.m. and 10:25 a.m.
- 10:30 a.m. and 10:55 a.m.
- 10:15 a.m. and 10:45 a.m.
- 10:30 a.m. and 11:00 a.m.
- 10:45 a.m. and 11:30 a.m.
- 10:55 a.m. and 11:25 a.m.
- 11:00 a.m. and 11:15 a.m.
we start from the earliest time as
9:00 a.m. and 9:45 a.m which is (1).
After the talk is finished we pick the nearest time for another talk which starts at
9:50 a.m. and 10:15 a.m which is (3).
After this talk we again pick the nearest time for another talk which becomes
10:30 a.m. and 10:55 a.m which is (6).
and lastly
10:45 a.m. and 11:30 a.m which is (9).
Note: we didn't choose other times because we cannot talk at 2 or 3 places at the same time. so we pick another when one talk is finished.
thus the answer is (1) - (3) - (6) - (9) as the largest number of talks scheduled.