Answer:
I think the answer is either c or d. but i think your answer is good
Step-by-step explanation:
1/4. and. 1/12. will do that.
he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).
Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.
<span>8-5x=8+2x is to be solved for x.
Group the x terms together: </span><span>8=8+2x+5x => 0 = 7x => x = 0</span>
Answer:
The value of ”c” can by found by this formula: (b/2)^2. In this equation the ”b” is 6. So, (6/3)^2=3^2=9.
The value of “c” that completes the square is 9.
:)
