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3 years ago

What is the conversion factor to convert kilometers to miles?

Mathematics

1 answer:

GREYUIT [131]3 years ago

6 0

Answer:

1 kilometer = 0.621371 mile

mile = kilometer * 0.621371

Step-by-step explanation:

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Is 0.7777.... a rational or irrational number and why

xxTIMURxx [149]

Answer:

irrational.

Step-by-step explanation:

0.7777... repeats and does not end so it is irrational

6 0

3 years ago

Read 2 more answers

Percy plotted the points (5,6)

Annette [7]

Answer:

1,6 and 6,6

Step-by-step explanation:

since they are on the same y-axis, changing the x-value shouldn't matter.

3 0

2 years ago

Read 2 more answers

Find the distance between the points (11, 4) and (10, 5). 1 2

Debora [2.8K]

Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(11,4)(10,5)

d = sqrt (10 - 11)^2 + (5 - 4)^2
d = sqrt (-1^2) + (1^2)
d = sqrt (1 + 1)
d = sqrt 2
d = 1.41 <===

3 0

3 years ago

Read 2 more answers

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

3 years ago

((5 - -5) x (9 + 3) /4)-10= enter your answer in the box 66 points pls help

Sergio039 [100]

Answer:

uhtvdbwiethweieigwhijgiwhgjwogw

Step-by-step explanation:

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7 0

2 years ago