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3 years ago

What is the conversion factor to convert kilometers to miles?

Mathematics

1 answer:

GREYUIT [131]3 years ago

6 0

Answer:

1 kilometer = 0.621371 mile

mile = kilometer * 0.621371

Step-by-step explanation:

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Linda bought a cube jewelry box. The volume of the jewelry box is 64 cubic inches. What is the edge length of Linda’s jewelry bo

yawa3891 [41]

Answer:

The edge length will be equal to 4 inches.

Step-by-step explanation:

The volume of a cube = s * s * s (in which s represent side of the cube)

V = s * s * s

V = s³

64 = s³

64 = 4³

So edge length of the cube will be 4 inches.

7 0

2 years ago

HELP Plssss..... The m

hammer [34]

Answer:

Step-by-step explanation:

Hey there!!!

According to the question,

Angle P is three less than twice less of an angle Q.

Then, let angle Q be x then angle P is 2x-3.

Now, it has also given that they are supplementary angle.

We know that the sum of supplementary angle is 180°.

Therefore, x+ 2x - 3°=180°.

Or, 3x = 180°-3°

Or, x = 177°/3

Therefore the measure of angle Q is 59° and P is 2×59°-3°= 121°.

Hope it helps....

6 0

3 years ago

What is 26 divided by 10.92

Bezzdna [24]

26 divided by 10.92 equals 2.380952

7 0

2 years ago

PLEASE HELP, I’LL GIVE BRAINLIST!

Alekssandra [29.7K]

Answer:

your answer would be 4/12 because there are 4 red marbles and 12 marbles total

Step-by-step explanation:

6 0

3 years ago

You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites. Assume you obtain a r

kicyunya [14]

Answer:

a) 0.2316 = 23.16% probability that 0 carry intestinal parasites.

b) 0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

Step-by-step explanation:

For each trout, there are only two possible outcomes. Either they carry intestinal parasites, or they do not. Trouts are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites.

This means that $p = 0.15$

Assume you obtain a random sample of 9 individuals from this population:

This means that $n = 9$

a. Calculate the probability that __ (last digit of your ID number) carry intestinal parasites.

Last digit is 0, so:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316$

0.2316 = 23.16% probability that 0 carry intestinal parasites.

b. Calculate the probability that at least two individuals carry intestinal parasites.

This is

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316$

$P(X = 1) = C_{9,1}.(0.15)^{1}.(0.85)^{8} = 0.3679$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2316 + 0.3679 = 0.5995$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5995 = 0.4005$

0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

5 0

2 years ago