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3 years ago

Which expression below gives the average rate of change of the function g(x) = -x^2 - 4x on the interval 6 ≤ x ≤ 8 ?

Mathematics

2 answers:

Katyanochek1 [597]3 years ago

4 0

Answer:

1st Option

Step-by-step explanation:

Average rate of change formula: $\frac{f(a) - f(b)}{a-b}$

Simply plug in 8 as a and 6 as b.

Gnesinka [82]3 years ago

3 0

Answer:

Step-by-step explanation:

Δy /Δx = (y2 - y1)/(x2 - x1) = [g(x2) - g(x1)]/(x2 - x1)

[g(x2) - g(x1)]/(x2 - x1) =[g(8) - g(6)]/(8 - 6) = $\frac{[-8^{2}-4(8)]-[-6^{2}-4(6)]}{8-6}$

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(01.05) Use the graph below to answer this question: graph of line going through negative 1, 4 and 2, 0 Find the average rate of

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1) Find the graph of a line passing through (-1, 4) and (2, 0).

The slope of two points can be determined by dividing the difference of y-values by the difference of x-values:

$\frac{4-0}{-1-2} =\frac{4}{-3}$

The slope of this equation is -4/3. Inputting this into the slope-intercept form of an equation, we get:

$y=\frac{-4}{3} x+b$

To find b, substitute x and y for one of the given coordinate pairs:

0 = (-4/3)(2) + b

0 = -8/3 + b

8/3 = b

Substitute the b value into the equation to finish the line:

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2 years ago

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Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$

Step 6: Find Slope at Given Point

[Algebra] Substitute in x: $y''(-1) = \frac{8}{(-1+2)^3}$
[Algebra] Evaluate: $y''(-1) =8$

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Answer:

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Step-by-step explanation:

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sergejj [24]

Answer:

Step-by-step explanation:

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