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1 year ago

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In this exercise, you'll use the formula for the probability of the complement of an event. another game you’ve set up at casino

night involves rolling a fair six-sided die followed by tossing a fair coin. in this game, players earn points depending on the number they get on the die and which side of the coin turns up. for example, the player earns 5 points for getting (2, tails). question 1 find the total number of possible outcomes in each trial of this game.

1 answer:

anyanavicka [17]1 year ago

5 0

8 games possible in a trial

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Algebra 2 inverse functions

Mashutka [201]

Answer:

The inverse function is:

{(1,8), (2,-1), (5,10), (-3,-3)}

Step-by-step explanation:

When a function is represented in the form of ordered pairs, the first element of each ordered pair is the input and the second element in each ordered pair is the output. In the inverse of a function the input becomes output and the output becomes input.

Given function is:

{(8,1), (-1,2), (10,5), (-3,-3)}

Reversing the order of elements of ordered pairs will given us the inverse function.

The inverse function is:

{(1,8), (2,-1), (5,10), (-3,-3)}

5 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

A scale drawing of an NFL god post uses a

Alex17521 [72]

It would be 455 inches because you divide 5/2 and it is 2.5 then you multiply it by 182 which is 455

6 0

2 years ago

Find the value of x<br> A.)25<br> B.)140<br> C.)5<br> D.)1

Vlada [557]

Answer:

25 = x

Step-by-step explanation:

The angles are vertical angles and vertical angles are equal

5x+15 = 6x -10

Subtract 5x from each side

5x-5x+15 = 6x-5x -10

15 = x - 10

Add 10 to each side

15+10 = x-10+10

25 = x

5 0

2 years ago

Read 2 more answers

Could someone please do this for me ASAP this is for math!

frutty [35]

Answer:

Step-by-step explanation:

$x^{2}$ +x-20

use FOIL

(x - 4)(x+5)

x-4=0

x+5=0

4 and negative 5 are the factors

8 0

2 years ago