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zloy xaker [14]
4 years ago
5

A gardener is watering his two flower beds with an oscillating sprinkler. The oscillating sprinkler adjusts the angle the water

exits the sprinkler head so that both flower beds are watered without moving the location of the sprinkler head. First, water from the sprinkler is shot up into the air in an arch and leaves the sprinkler head with a speed of 55m/s at an angle of θ = 35◦ above the horizontal. The water lands in the center of the flower beds. Then sprinkler bar rotates reducing its angle to an angle of θ = 30◦ above the horizontal and the water lands in the center of the second flower bed. The flower bed closest to the sprinkler is at the same height as the sprinkler head. Water reaches the flower bed closest to the sprinkler when the water is at an angle of 30◦ . The flower bed farthest from the sprinkler is in a raised flower bed, so the flowers are a height of 0.75 m above the ground. Assume the sprinkler head doesn’t change height as it rotates. How far apart are the centers of two flower boxes from each other? (Note: the gardener notices it takes longer than a half a second for the water to reach each of the flower beds)
Mathematics
1 answer:
Wittaler [7]4 years ago
6 0

Answer:

Step-by-step explanation:

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