3 years ago

Find the solution for: . log(3x-1)+log2=log4+log(x+2)

2 answers:

8 0

㏒(3x - 1) + ㏒(2) = ㏒(4) + ㏒(x + 2)
㏒(2(3x - 1)) = ㏒(4(x + 2))
㏒(2(3x) - 2(1)) = ㏒(4(x) + 4(2))
㏒(6x - 2) = ㏒(4x + 8)
6x - 2 = 4x + 8
- 4x - 4x
2x - 2 = 8
+ 2 + 2
2x = 10
2 2
x = 5

egoroff_w [7]3 years ago

3 0

Answer:

x=5

Step-by-step explanation:

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