1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Archy [21]
3 years ago
12

Question 1: The Millers have hired an interior designer to decorate their family room. they want to have a 22" by 30" oil painti

ng frame and incorporated in the design plan. if the designer chooses molding that is 4" Wide and is priced at $1.45 per inch, how much will the molding cost (Before Tax)
​
Mathematics
1 answer:
____ [38]3 years ago
6 0

Answer: Total molding cost is $197.20.

Step-by-step explanation:

Since we have given that

Length of oil painting frame = 22 inch

Width of oil painting frame = 30 inch

Width for molding = 4 inches

So, Length after molding would be

4+22+4 = 30 inches

Width after molding would be

4+30+4 = 38 inches

So, Perimeter of molding would be

2(L+B)\\\\=2(30+38)\\\\=2\times 68\\\\=136\ inches

Cost per inch = $1.45

So, Total molding cost would be

1.45\times 136\\\\=\$197.20

Hence, Total molding cost is $197.20.

You might be interested in
On a multiple choice test with 17 questions, each question has four possible answer, one of which is correct. For students who g
Virty [35]

Answer:

C. 4.3

Step-by-step explanation:

Given that

n = 17

P = 1/4

Using binomial

Mean = np

Mean = 17 × (1/4)

= 17 × .25

= 4.25

Approximately = 4.3

3 0
3 years ago
Show that √(1-cos A/1+cos A) =cosec A - cot A​
Gennadij [26K]

Hi there!

\sqrt{\frac{1-cosA}{1+cosA}} =

We can begin by multiplying by its conjugate:

\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}}  = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =

Simplify using the identity:

1 - cos^2A = sin^2A

\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =

Take the square root of the expression:

{\frac{sinA}{1+cosA} =

Multiply again by the conjugate to get a SINGLE term in the denominator:

{\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\

Simplify:

{\frac{sinA(1-cosA)}{1-cos^2A} =

Use the above trig identity one more:

{\frac{sinA(1-cosA)}{sin^2A} =

Cancel out sinA:

{\frac{(1-cosA)}{sinA}  =

Split the fraction into two:

{\frac{1}{sinA}   - \frac{cosA}{sinA} =

Recall:

1/sinA = cscA\\\\cosA/sinA = cotA

Simplify:

\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}

5 0
2 years ago
Can somebody help me solve this?
Nookie1986 [14]

Answer:

z = 3.2 units

Step-by-step explanation:

sin 76°/z = sin 51°/2.6

cross-multiply to get:

z·(sin 51°) = 2.6·(sin 76°)

z = 2.6·(sin 76°) ÷ (sin 51°)

z = 3.2

3 0
3 years ago
jim is planning a party. he spends $150 on a room for the party. he also spends $16.50 per person for food. jim finds the total
meriva
$577.50is the amount he paid.
8 0
3 years ago
What is the area of the triangle below (in square units)?<br> 10 mm<br> 90mm
bixtya [17]

Answer:

450

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Other questions:
  • 1) Which equation could be used to estimate the population of Oak City in 10 years?
    7·1 answer
  • Hello please help on number 3
    10·1 answer
  • If i get on the scale with my dog and my baby and weigh 100lbs more than the 2 of them combined, the dog weighs 60% less than th
    10·1 answer
  • Evaluate cos(tan^-1 0)
    8·1 answer
  • Is this relation a function?
    13·1 answer
  • I will give you brainlest and 5 stars if you answer this correctly
    13·2 answers
  • EXTRA POINTS <br> Is the transformation a dilation, rotation, reflection, or a translation?
    10·2 answers
  • Jacob made a scale drawing of the auditorium. The scale of the drawing was 3 inches : 2 feet. If the stage is 45 inches in the d
    6·2 answers
  • Given the expression -15(10 2/3), Rewrite the expression using Distributive Property.
    7·1 answer
  • Please help me with my assignment
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!