The current in the coil is 297 A
Explanation:
The magnetic field of a circular coil carrying a current is given by

where
is the vacuum permeability
N is the number of turns in the coil
I is the current in the coil
R is the radius of the coil
For the coil in this problem, we have:

R = 20 cm = 0.20 m
N = 15
Solving the equation for I, we find the current in the coil:

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Answer:
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Explanation:
The formula to be used here is
Q = It
where Q is the quantity of electricity and it is measured coulombs (C); 2.8 × 10⁻⁸ C or 0.000000028 C
I is current and it is measured in ampere (amps or A); unknown
t is time and it is measured in seconds (s); 0.05 s
Since, average current is what is unknown
I =Q/t
I = 0.000000028/0.05
I = 5.6 × 10⁻⁷ A
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Answer:
F = 0N
Explanation:
The force between two charges is given by

where r is the distance between the charges and K is the Coulomb's constant
(k=8-89*10^9Nm^2/C^2)
The force in the first charge is only the sum of the forces due to the other charges. Hence we have


Ft=0N
Hope this helps!!
Answer:
I think the correct answer is B.
Answer:
The distance that you marginally able to discern that there are two headlights rather than a single light source is 6.084 km
Explanation:
Given:
d = distance = 0.679 m
λ = wavelength of the light = 537 nm = 537x10⁻⁹m
dp = pupil diameter = 4.81 mm = 0.00481 m
Question: What distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source, dx = ?
For the separation of the peak from the central maximum it is:

In this case, the two small sources of the headlights have the same angle as the images that form inside the eye
