1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sladkih [1.3K]
3 years ago
9

1. Differentiate between speed and velocity.

Physics
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

1. Speed and velocity both involve a numeric rate describing the distance traveled by a body in a unit of time. However, speed describes the rate of a body traveling in any direction in a unit of time, while velocity describes the rate of a body traveling in a particular direction in a unit of time.

2. Answers may vary, but should resemble the following:

Average velocity explains the velocity the body traveled overall, not taking into consideration each spot in the trip. If a car moves at 65 km/h on average, it may have slowed down for some parts and sped up for others. Overall though, it would have made a certain distance of travel within a specified unit of time that totals the average velocity of 65 km/h.

Instantaneous velocity explains the velocity of a body at a particular instant of the trip. The instantaneous velocity of a car stopped at a stop sign would be 0 m/s even if it was moving before and will continue to move after this stop. The velocity at that particular instant is the instantaneous velocity.

Uniform velocity is when the distance being covered is changing uniformly with time. For example, if a car moves 20 km every 30 minutes and continues to do so in the same direction, it's traveling with a uniform velocity.

3. a=v2−v1t

a=20 m/s−60 m/s6 s

a=−406

a = –6.7 m/s2

4. v2 = v1 + at

v2 = 14 m/s + (3 m/s2 × 6 s)

v2 = 14 + 18

v2 = 32 m/s

5. v=st

v=375 km5 h

v = 75 km/h  

6. First, convert the minutes to seconds. Since there are 60 seconds in one minute, multiply:

60 × 15 (minutes) = 900 seconds

s = v × t

s = 6 m/s × 900 s

s = 5,400 m

7. t=sv

t=80 km35 km/hr

t = 2.29 hr

8. a=v2−v1t

a=50 m/s−15 m/s4 s

a=35 m/s4 s

a = 8.75 m/s2

9. vav=v1+v22

vav=15 m/s+50 m/s2

vav=65 m/s2

vav = 32.5 m/s

10. a=v2−v1t

a=0 m/s−11.5 m/s3.5 s

a = –3.29 m/s2

Explanation:

You might be interested in
In a Broadway performance, an 83.0-kg actor swings from a R = 3.90-m-long cable that is horizontal when he starts. At the bottom
Veseljchak [2.6K]

Answer:

h = 2.821\,m

Explanation:

The speed of the actor before the collision is found by means of the Principle of Energy Conservation:

(83\,kg)\cdot(9.807\,\frac{m}{s})\cdot (3.90\,m) = \frac{1}{2}\cdot (83\,kg)\cdot v^{2}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (3.90\,m)}

v \approx 8.746\,\frac{m}{s}

The speed after the inelastic collision is obtained by using the Principle of Momentum Conservation:

(83\,kg)\cdot (8.746\,\frac{m}{s} )+(55\,kg)\cdot (0\,\frac{m}{s} ) = (83\,kg + 55\,kg)\cdot v

v = 5.260\,\frac{m}{s}

Lastly, the maximum height is determined by using the Principle of Energy Conservation again:

\frac{1}{2}\cdot (138\,kg)\cdot (5.260\,\frac{m}{s} )^{2} = (138\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot h

h = \frac{(5.260\,\frac{m}{s} )^{2}}{9.807\,\frac{m}{s^{2}} }

h = 2.821\,m

8 0
3 years ago
If the hiker starts climbing at an elevation of 350 ft, what will their change in gravitational potential energy be, in joules,
Kitty [74]

Answer:

352,088.37888Joules

Explanation:

Complete question;

A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.

A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)

Chane in potential energy is expressed as;

ΔGPH = mgΔH

m is the mass of the hiker

g is the acceleration due to gravity;

ΔH is the change in height

Given

m = 53kg

g = 9.8m/s²

ΔH = 2574-350 = 2224ft

since 1ft = 0.3048m

2224ft = (2224*0.3048)m = 677.8752m

Required

Gravitational potential energy

Substitute the values into the formula;

ΔGPH = mgΔH

ΔGPH = 53(9.8)(677.8752)

ΔGPH = 352,088.37888Joules

Hence the gravitational potential energy is 352,088.37888Joules

7 0
3 years ago
Which two statements about composite materials are true?
Lostsunrise [7]

Answer:

Here down below is 3 things true about composite materials

Explanation:

-They’re made up of more than one substance.

-They have the same or similar properties as the materials used to make them.

-They’re always made of metal.

-They’re readily available in nature.

4 0
3 years ago
What is the main source of energy
jolli1 [7]
Sun is the main source of energy
8 0
3 years ago
Read 2 more answers
Which of the following is not an application of Doppler technology?
allsm [11]
The correct answer to the question above is The third Option: C; ultrasound imaging of the liver. The ultrasound imaging of the liver is definitely not an application of Doppler technology.

Hope this helps! :)
8 0
3 years ago
Read 2 more answers
Other questions:
  • Help please I really need help in this one
    13·1 answer
  • Assume that you have a mass of 50.0kg and earth has a mass of 5.97x10kg.The radius of earth is 6.38x10m.What is the force of gra
    12·1 answer
  • Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 22 cm apart. The sound
    8·1 answer
  • Which piece of evidence contradicts the steady state theory?
    14·2 answers
  • What two things must you know to find the <br> momentum of an object? <br> :( anyone?
    13·2 answers
  • What is the difference between transverse and longitudinal waves? Transverse waves always travel at smaller speeds than do longi
    15·1 answer
  • Tori applies a force of 20 newtons to move a bookcase with a mass of 40 kg. What
    9·1 answer
  • Ploughing field with harrow pulled by a tractor is a modern technology​
    12·1 answer
  • 7. Cellular respiration that uses oxygen is called ​
    9·1 answer
  • A bullet with a mass of 0.04-kg is traveling horizontally at 1400 m/s when it strikes a stationary target that is balanced on th
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!