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sladkih [1.3K]
3 years ago
9

1. Differentiate between speed and velocity.

Physics
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

1. Speed and velocity both involve a numeric rate describing the distance traveled by a body in a unit of time. However, speed describes the rate of a body traveling in any direction in a unit of time, while velocity describes the rate of a body traveling in a particular direction in a unit of time.

2. Answers may vary, but should resemble the following:

Average velocity explains the velocity the body traveled overall, not taking into consideration each spot in the trip. If a car moves at 65 km/h on average, it may have slowed down for some parts and sped up for others. Overall though, it would have made a certain distance of travel within a specified unit of time that totals the average velocity of 65 km/h.

Instantaneous velocity explains the velocity of a body at a particular instant of the trip. The instantaneous velocity of a car stopped at a stop sign would be 0 m/s even if it was moving before and will continue to move after this stop. The velocity at that particular instant is the instantaneous velocity.

Uniform velocity is when the distance being covered is changing uniformly with time. For example, if a car moves 20 km every 30 minutes and continues to do so in the same direction, it's traveling with a uniform velocity.

3. a=v2−v1t

a=20 m/s−60 m/s6 s

a=−406

a = –6.7 m/s2

4. v2 = v1 + at

v2 = 14 m/s + (3 m/s2 × 6 s)

v2 = 14 + 18

v2 = 32 m/s

5. v=st

v=375 km5 h

v = 75 km/h  

6. First, convert the minutes to seconds. Since there are 60 seconds in one minute, multiply:

60 × 15 (minutes) = 900 seconds

s = v × t

s = 6 m/s × 900 s

s = 5,400 m

7. t=sv

t=80 km35 km/hr

t = 2.29 hr

8. a=v2−v1t

a=50 m/s−15 m/s4 s

a=35 m/s4 s

a = 8.75 m/s2

9. vav=v1+v22

vav=15 m/s+50 m/s2

vav=65 m/s2

vav = 32.5 m/s

10. a=v2−v1t

a=0 m/s−11.5 m/s3.5 s

a = –3.29 m/s2

Explanation:

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Answer:

Explanation:

We know that

Δr = r₁ - r₀

r₀ = 0 i + 0 j

r₁ = (162+137*Cos(31º)+137*Cos(-48º)) i + (0+137*Sin(31º)+137*Sin(-48º)) j = (371.1028 i - 31.2506 j) ft

Δr = r₁ - r₀ = (371.1028 i - 31.2506 j) - (0 i + 0 j) = (371.1028 i - 31.2506 j) ft

Magnitude:

Δr = √((371.1028)²+(-31.2506)²) = 372.4163 ft

Angle:

tan θ = (- 31.2506 / 371.1028) = -0.0839   ⇒   θ = tan⁻¹(-0.0839) = - 4.8135º

(below the horizontal).

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4 years ago
Which method of separation of mixtures is vital to life on earth?
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Answer:

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Explanation:

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3 years ago
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The box is pushed to the right with a force of 40 Newtons and it just begins to move what is the maximum static frictional force
Vesnalui [34]

Answer:

The maximum static frictional force is 40N.

Explanation:

When an object of mass M is on a surface with a coefficient of static friction μ, there is a minimum force that you need to apply to the object in order to "break" the coefficient of static friction and be able to move the object (Called the threshold of motion, once the object is moving we have a coefficient of kinetic friction, which is smaller than the one for static friction).

This coefficient defines the maximum static friction force that we can have.

So if we apply a small force and we start to increase it, the static frictional force will be equal to our force until it reaches its maximum, and then we can move the object and now we will have frictional force.

In this case, we know that we apply a force of 40N and the object just starts to move.

Then we can assume that we are just at the point of transition between static frictional force and kinetic frictional force (the threshold of motion), thus, 40 N is the maximum of the static frictional force.

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3 years ago
The distance that a person can see to the horizon on a clear day from a point above the surface of Earth varies directly as the
lara [203]

Answer:

900 m ( 0.9 km)

Explanation:

from the question we have the following

first person's height  (h) = 100 m above the earths surface

distance to the horizon that can be seen (s)  = 15 km = 15,000 m

second person's height  (h1) = 36 m

distance to the horizon that can be seen (s1) = ?

take note that the distance (s) a person can see = square root of the person's height

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from the height and the distance the first person can see we can get the value of K

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K = 150

now putting the value of K and the height of the second person into the equation we can get the distance into the horizon the person can see

s =  \sqrt{36} x 150

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therefore the second person who is 36 m above the surface can see 900 m ( 0.9 km) into the horizon

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Which statement best describes the relationship between temperature and thermal energy?
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Overall, when temp goes up, thermal energy goes up, which leads to an increase in kinetic energy.</span>
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