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enyata [817]
3 years ago
12

What is the least common multiple (LCM) of 3 and 7?

Mathematics
2 answers:
andriy [413]3 years ago
8 0

it is 21 :)))))))))))))))

vova2212 [387]3 years ago
4 0

Answer:

21

Step-by-step explanation:

LCM(3,7) = ( 3 × 7) / 1

LCM(3,7) = 21 / 1

LCM(3,7) = 21

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statuscvo [17]

Answer:

the anser is 4 im pretty sure.

Step-by-step explanation: 3*6 is 18 and 4*4 is 16. 18 minus 16 is 2 multiplied by the other 2 is 4.

7 0
2 years ago
Read 2 more answers
5(y-4)=7(2y+1)<br>I need the answer​
8_murik_8 [283]

Answer: y = -3

Move all terms containing y to the left, all other terms to the right

<u>Add -14y to each side of the equation</u>

<u></u>-20 + 5y + -14y = 7 + 14y + -14y<u></u>

<u></u>

<u>Combine like terms: 5y + -14y = -9y </u>

<u></u>-20 + -9y = 7 + 14y + -14y<u></u>

<u></u>

<u>Combine like terms: 14y + -14y = 0 </u>

<u></u>-20 + -9y = 7 + 0\\-20 + -9y = 7<u></u>

<u></u>

<u>Add '20' to each side of the equation</u>

<u></u>-20 + 20 + -9y = 7 + 20<u></u>

<u></u>

<u>Combine like terms: -20 + 20 = 0 </u>

<u></u>0 + -9y = 7 + 20\\-9y = 7 + 20<u></u>

<u></u>

<u>Combine like terms: 7 + 20 = 27 </u>

<u></u>-9y = 27<u></u>

<u></u>

<u>Divide each side by -9</u>

<u></u>-9y/9=27/-9\\y=-3<u></u>

8 0
3 years ago
If the sum of six consecutive even integers is 306, what is the smallest of the six integers
Neko [114]

306/6 is 51 is you add one to one side and take away the other the six numbers become: 46, 48, 50, 52, 54, 56 as you added one to one side substituting the other you took away from, therefore the smallest would be 46.

4 0
3 years ago
First answer gets a thanks
Karolina [17]
I would have to say A - Mean; because the data is skewed and there are outliers.

This is because the median of this would not be accurate for the number of kids that read no books and the random three kids that read ten. Mean, however, would find the true median within the plot and utilize and take into account the outliers and how skewed the data is.

Hope this helps!
7 0
3 years ago
Read 2 more answers
Please help! I’ve always had trouble with these questions. It’d be a big hand.
deff fn [24]

2. c = 47,000 × n, where c is the cost of n number of bears.

3. a) The cost to ride 5 rides = $20.50, the cost to ride 8 rides = $28.00

The equation for the pattern, C(x) = 15.50 + 2.50 (r - 3), where C is the cost and r is the number of rides.

b) The cost to ride 12 rides = $36.00.

Step-by-step explanation:

Step 1; To find the cost of one bear, we divide the cost of bears by the number.

If 4 bears cost $188,000, 1 bear costs = \frac{188000}{4} = $47,000.

If 7 bears cost $329,000, 1 bear costs = \frac{329,000}{7} = $47,000.

So the equation is c = 47,000 × n, where c is the cost to buy n bears.

Step 2; For every additional ride, the price increases by $2.50. So the equation for the pattern is C(x) = 13.50 + 2.50 (x - 3).

When the number of rides is 5, C(5) = 15.50 + 2.50 (5-3) = 15.50 + 2.50 (2) = 15.50 + 5.0 = $20.50.

When the number of rides is 8, C(8) = 15.50 + 2.50 (8-3) = 15.50 + 2.50 (5) = 15.50 + 12.50 = $28.00.

When the number of rides is 12, C(12) = 15.50 + 2.50 (12-3) = 15.50 + 2.50 (9) = 13.50 + 22.5 = $36.00.

3 0
3 years ago
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