Answer:
f(t) = 4 - 3t + 2t^2
Step-by-step explanation:
Given:
f(t) = a + bt + ct^2
Differentiate w.r.t. "t"
f'(t) = b + 2ct
1) f(1) = 3
a + b +c = 3...........1)
2) f(2) = 6
a + 2b + 4c = 6.........2)
3) f'(1) = 1
b + 2c = 1 ...............3)
Solving above three simultaneous equations:
a = 4
b = -3
c = 2
Therefore equation becomes:
f(t) = 4 + (-3)t + (2)t^2
Answer:
y= 3x +9
Step-by-step explanation:
m= 3
The y-intercept of the line that passes through the given point (0,9) is
9 = 0(3) + b
b= 9
The equation of the line that passes through the given point (0,9) is
y =mx +b
y = 3x +9
Answer:
1,6,2 and 5
Step-by-step explanation:
(2x/5)² . (1x⁴/4)^-1
=(2²x²/5²) . (4/x⁴)
=4x²/25 × 4/x⁴
= 16/25x²
Answer:
-2c^2 + c
Step-by-step explanation:
