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Marat540 [252]
3 years ago
7

Find the largest number δ such that if |x − 1| < δ, then |5x − 5| < ε, where ε = 0.1. δ ≤ repeat and determine δ with ε =

0.01.
Mathematics
1 answer:
Leya [2.2K]3 years ago
4 0
|5x-5|=5|x-1|

So for \varepsilon=0.1, we get \delta=50; for \varepsilon=0.01, we get \delta=500.
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sineoko [7]
12/5 is the answer!

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5 0
3 years ago
Read 2 more answers
The base of a triangle is 9/4 times of its height. If the area of triangle is 144 cm2. Find the height and the base.
Mazyrski [523]

Step-by-step explanation:

Given that the base of triangle is 9/4 times of its height . And area is 144 cm² . Let the height be h , then its base be 9h/4 .

<u>•</u><u> </u><u>Acco</u><u>rding</u><u> </u><u>to</u><u> </u><u>Question</u><u> </u><u>:</u><u>-</u><u> </u>

\tt\to Area_{(\triangle)}=\dfrac{base\times height}{2}\\\\\tt\to 144cm^2 = \dfrac{9h\times h}{4\times 2 } \\\\\tt\to h^2 =\dfrac{12\times 12 \times 2 \times 2 }{3\times 3 }\\\\\tt\to h =\sqrt{\dfrac{12\times 12 \times 2 \times 2 }{3\times 3 }}\\\\\tt\to h =\dfrac{(12)(2)}{3} \\\\\tt\to \boxed{\orange{\tt h = 8 cm }}

Therefore ,

  • Height = h = 8cm .
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5 0
2 years ago
Which statement regarding the interior and exterior angles of a triangle is true?
yulyashka [42]
Draw a triangle on your paper and extend the base of the triangle so it extends past the base angle.  The base angle inside the triangle is the interior angle and the one outside the triangle between the extended line and the outside of the interior angle is the exterior angle.  A straight line has a measure of 180 degrees.  That means that the interior angle + the exterior angle = 180.  So they are supplementary by definition of supplementary angles.  A is the only choice above that applies.
4 0
3 years ago
I WILL MARK BRAINIEST<br> PLEASE HELP ASAP ITS DUE
Daniel [21]

Answer:

A) 1 : 4

B) 1 : 2

C) Base of M = 10 units

Step-by-step explanation:

A)

The ratio of the area of triangle M to triangle N

\frac {40}{160}= \frac{1}{4} = 1 : 4

B)

The ratio of the side lengths of triangle M to triangle N

\sqrt{ \frac {40}{160}} = \sqrt{\frac{1}{4}} \\\\={\frac{1}{2}} \\\\=1 : 2

C) Let the base of triangle M be b units.

\sqrt{ \frac {40}{160}} = \frac{b}{20}\\\\\frac{1}{2}=  \frac{b}{20}\\\\2b = 20\\\\b = \frac{20}{2} \\\\b = 10

8 0
2 years ago
Consider the rectangle shown
emmainna [20.7K]

Step-by-step explanation:

<em>Perimeter </em><em>of </em><em>a </em><em>rectangle</em><em>=</em><em> </em><em>2</em><em>L</em><em> </em><em>+</em><em> </em><em>2</em><em>W</em>

<em>let </em><em>the </em><em>length </em><em>be </em>2x-1<em> </em><em>and </em><em>breadth</em><em>/</em><em> </em><em>width </em><em>=</em><em> </em>3x+5

52= 2x-1 + 3x+5

52= 5x +4

<em> </em><em>collect </em><em>like </em><em>terms</em><em>;</em>

52-4 = 5x

48=5x

<em>divide </em><em>by </em><em>the </em><em>co- </em><em>efficient </em><em>of </em><em>X</em>

<em>x=</em><em> </em><em>9</em><em>.</em><em>6</em><em>.</em>

<em>hope </em><em>it </em><em>helps.</em><em> </em><em>pls </em><em>like </em><em>and </em><em>follow </em><em>:-)</em><em>:-)</em>

8 0
1 year ago
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