You want 9x^2 + bx + 9a to be a perfect square trinomial. Note that 9 x 2 is incorrect and should be written as 9x^2, where "^" represents "exponentiation."
What about a? Are we supposed to find a also?
One way in which to do this problem is to factor 9 out of the trinomial:
9 (x^2 + (b/9)x + a )
Concentrate now on making x^2 + (b/9)x + a into a perfect square trinomial.
x^2 + (b/9)x + a
Take half of the coefficient (b/9) and square the result: [(b/9)/2]^2 = b^2/81.
Then, x^2 + (b/9)x + b^2/81 - b^2/81 + a.
The above quadratic expression can be re-written as
(x + b/9)^2 - b^2/81 + a. This is a perfect square trinomial if
-b^2/81 + a = 0. Solve for b: b^2/81 = a,
b/9 = sqrt(a)
b = 9 sqrt a
You know someone is just going to look it up? so save yourself the time and pts and look it up yourself. and the answer is <span>151,600</span>
Answer: -4860y^2
Solution:
81 x (5y x 6) x (-2y)
-81 x 5y x 6 x 2y
= -4860y^2
Step-by-step explanation:
The number of way to select 2 employees from 40 is 40C2.
The number of way to select 2 employees from 22 is 22C2.
So the probability of the two employees having single-vision correction is just the number of ways to select the 22 employees (22C2) divided by the total number of ways to select 2 employees (40C2).
22C2 / 40C2 = 77/260
We can use the same technique for the bifocal employees.
18C2 / 40C2 = 51/260
Answer:
Part A:
I have attached the graph of this system of inequalities.
Part B:
Plug in (8,10) into both equations
10 > 3(8) + 10
10 > 24 + 10
10 > 34
This is false!
10 < (-3/4)(8) - 1
10 < (-3)(2) - 1
10 < -6 - 1
10 < -7
This is also false!
So, (8,10) is not included in the solution area for the system.
Step-by-step explanation:
